Given:
The x and y axis are tangent to a circle with radius 3 units. 
To find:
The standard form of the circle.
Solution:
It is given that the radius of the circle is 3 units and x and y axis are tangent to the circle.
We know that the radius of the circle are perpendicular to the tangent at the point of tangency.
It means center of the circle is 3 units from the y-axis and 3 units from the x-axis. So, the center of the circle is (3,3).
The standard form of a circle is:

Where, (h,k) is the center of the circle and r is the radius of the circle.
Putting  , we get
, we get


Therefore, the standard form of the given circle is  .
.
 
        
             
        
        
        
Answer:
y=2x-5
Step-by-step explanation:
The slope-intercept form of an equation looks like y=mx+b. Where m is the slope and b is the y-intercept. The slope is already given to us, so m is 2. 
To find b use the equation  . So, to find the y-intercept use b=-7-(2*-1). This equals b=-5.
. So, to find the y-intercept use b=-7-(2*-1). This equals b=-5.
So, plug in the values to get the final equation y=2x-5.
 
        
                    
             
        
        
        
Answer:
A
Step-by-step explanation:
Put brackets around the first two tems.
y = (x^2 - 8x) + 29
Take 1/2 coefficient of the linear term -8. Square that result. Add it inside the brackets.
1/2 (- 8) = - 4
(- 4)^2 = 16
y = (x^2 - 8x + 16) + 29
Subtract 16 outside the brackets.
y = (x^2 - 8x + 16) + 29 - 16  
Do the subtraction
y = (x^2 - 8x + 16) + 13
Represent what is inside the brackets as a square.
y = ( x - 4)^2 + 13
The answer is A
 
        
             
        
        
        
Equivalent expressions are expressions with the same value.
The equivalent expression of  is
 is 
Given that:

Open brackets

Collect like terms


Hence, the equivalent of  is
 is 
Read more about equivalent expressions at:
brainly.com/question/18257981
 
        
             
        
        
        
Answer:
I send you a pic 
Step-by-step explanation:
is that help?