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larisa [96]
3 years ago
7

Drag each pair of figures to the correct location on the table. Each pair of figures can be used more than once. Match the pairs

of figures to the transformations that can be used to form one figure from the other. For each pair of figures, there may be multiple types of transformations that work.

Mathematics
1 answer:
Tcecarenko [31]3 years ago
4 0

Answer:

Step-by-step explanation:

AB:

could be a reflection on a line with a positive slope greater than one or rotation 180 degrees (or 180 + any # of 360 degree rotations)

(reflection, rotation)

CD:

could be translated

could be reflected on a line with a negative slope of less than -1

(translation, reflection)

GH:

could be either reflected

or

translated

or

rotated 90 degrees or 270 degrees +whatever # of 360 degree rotations

or reflected about both x and y axis

(reflection, translation, rotation)

IJ:

could be reflected

or

rotated 180 degrees+ any number of 360 degree rotations

(reflection, rotation)

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Y = 2x – 5 2y – 4x =
nikklg [1K]

Answer:

2y-4x

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the difference: 26 44 – 18 44
pychu [463]
I'm not sure what the 26 and 44 is there for but I'm guessing u want to multiply so in order to find the difference u got to multiply both sides the subtract so the answer would be 352
3 0
3 years ago
The sum of the measures of angle Y and angle Z is 180 degrees. Angle Y measures (3x + 20) degrees and Angle Z measures x degrees
Minchanka [31]
A)
The question tells us that
y + z = 180
And
y=3x+20
z=x

So we put them in the first formula:

y + z = 180
(3x + 20) + x = 180

Add and get x to one side:
4x + 20 = 180
4x + 20 - 20 = 180-20
4x = 160
Divide both sides by 4
x = 40

B)
Put x back in to equation to get size of each angle:

Y =3x +20
Y=3(40)+20
Y=120+20
Y=140

Z=x
Z=40

Verify: y+z=180
140+40=180
180=180
8 0
2 years ago
The altitude of a triangle is increasing at a rate of 1 cm/ min while the area of the triangle is increasing at a rate of 2 cm2
serg [7]
Ya, calculus and related rates, such fun!




everything is changing with respect to t

altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min

area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min

base=db/dt

alright

area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt

ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b

so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min

therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt

the base is decreasing at 1.6cm/min
4 0
3 years ago
Multiply 4 and 7. Then, divide by q.
Makovka662 [10]

Answer:

28/q

Step-by-step explanation:

4 times 7 equals 28 and then divide 28 by q

5 0
3 years ago
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