Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500
Answer:
gametes, which grow into gametophyte.
Explanation:
Hepatitis 'C' may be dormant in the body for years before the signs and symptoms. Hepatitis A, B, and C are cause by a virus. Hepatitis A is also known as Infectious Hepatitis, Hepatitis B is also known as serum Hepatitis. Hepatitis C is a viral infection that causes liver inflammation, sometimes leading to serious liver damage, it spreads through contaminated blood.
The answer should be competitive inhibitors
A. An increase in the amount of acid rain can change the pH of soil in an ecosystem.
