All categories

4 years ago

Answer this pls. It's an emergancy

Mathematics

1 answer:

kkurt [141]4 years ago

8 0

Answer: -28

Showing the work:

= -43-(-15)

= -43--15

= -43+15

= -28

You might be interested in

The sentence three times the difference of -13 and 2 amounts to -45 written as an equation

Alinara [238K]

3(-13-2)= -45

Step-by-step explanation:

We need to write the equation of:

three times the difference of -13 and 2 amounts to -45 written as an equation

The equation is:

3(-13-2)= -45

Keywords: Convert Sentence into Equations

Learn more about Converting Sentence into Equations:

#learnwithBrainly

7 0

3 years ago

Solving Exponential and Logarithmic Equations In Exercise, solve for x. In 2x - In(3x - 1) = 0

LenKa [72]

Answer:

$\frac{-1}{3x^2-x}$

Step-by-step explanation:

If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)

using these information:

g(x)=ln2x then g'(x)= $\frac{(2x)'}{2x} =\frac{2}{2x}=\frac{1}{x}$

h(x)=In(3x - 1) then h'(x)= $\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}$

7 0

4 years ago

Find the length of EG: G C E B.

Lerok [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

On the 1st January 2014 Carol invested some money in a bank account.

Ghella [55]

Answer:

$\large \boxed{\text{\pounds 23 360.00}}$

Step-by-step explanation:

The formula for the accrued amount from compound interest is

$A = P \left(1 + \dfrac{r}{n}\right)^{nt}$

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:

r = 0.025

$\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}$

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

$\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}$

3. Summary

1 Jan 2014 P = £23 360.00

1 Jan 2015 A = 23 944.00

Withdrawal = -1 000.00

P = 22 944.00

1 Jan 2016 A = £23 517.60

5 0

3 years ago

Sue walks 1 mile to a store. About how far is this in metric units? A. 2 millimeters B. Centimeters C. 2 meters D. Kilometers pl

Andrei [34K]

Answer:

C meter

Step-by-step explanation

Did this in class luv hope this helps<3

4 0

3 years ago