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Lilit [14]
3 years ago
6

What is the rate of change to 2y=14x+6

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0

Answer:

7x-y=-3

Step-by-step explanation:

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Will mark brainliest help!
kakasveta [241]

Answer:

52.5

Step-by-step explanation:

Since ED ≈ AD, ∆AED is a isosceles triangle where <EAD and <AED has same angle measurement

Now, m<B = 105°, since ABCD is a parallelogram, <B = <D

so, m<ADC = 105° so, m<ADE = 180°-105° = 75°

Now, m<EAD+m<AED+m<ADE = 180°

or, m<AED+m<AED+m<ADE = 180°

or, x+x+75°=180°

or, 2x=180+75°

or, 2x=105°

or, x=52.5°

3 0
2 years ago
Which of the images above represents a proof of the Pythagorean Theorem? Explain your choice, and than explain how the figure pr
Vedmedyk [2.9K]
We don’t have any of the “images” to answer this question.
6 0
3 years ago
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Mark ran 213 mi. and Shaun ran 315 mi. Find the difference in the distance that they ran.
Nutka1998 [239]
102 miles you subtract them and get the results
3 0
2 years ago
write a equation for the vertical and horizonal lines passing through the points (4,1) I know x=4 and y=1 but what eles do I do?
Harlamova29_29 [7]
Well you solve the equation then find out what you dealing with
6 0
3 years ago
Some airlines have restrictions on the size of items of luggage that passengers are allowed to take with them. suppose that one
olga nikolaevna [1]
<span>Length, width, and height are all 68 cm. I am assuming that there's a formatting issue with this question and that the actual size limit is 204 cm. With that in mind, let's create a function giving the width of the box in terms of its height. So w = (204 - h)/2 Now let's create an expression giving the volume of the box in terms of height. v = lwh Since the width and length are the same, replace l with w v = wwh And now replace w with (102-h/2) v = (102-h/2)(102-h/2)h And expand the equation. v = (102-h/2)(102-h/2)h v = (10404 -51h - 51h + 0.25h^2)h v = (10404 -102h + 0.25h^2)h v = 10404h -102h^2 + 0.25h^3 Since we're looking for a maximum, that can only happen when the slope of the above equation is equal to 0. The first derivative will tell you the slope of the function at each point. So let's calculate the first derivative. For each term, multiply the coefficient by the exponent and then subtract 1 from the exponent. So: v = 10404h - 102h^2 + 0.25h^3 v = 10404h^1 - 102h^2 + 0.25h^3 v' = 1*10404h^(1-1) - 2*102h^(2-1) +3*0.25h^(3-1) v' = 10404h^0 - 204h^1 + 0.75h^2 v' = 10404 - 204h^1 + 0.75h^2 We now have a quadratic equation with A=0.75, B=-204, and C=10404. Use the quadratic formula to find the roots, which are 68 and 204. These 2 zeros represent a local minimum and a local maximum. The value 204 is obviously the local minimum since the box would have a width and length of 0 resulting in a volume of 0. So the height must be 68 which means the length and width are (204 - 68)/2 = 136/2 = 68. To prove that 68 is the optimal height, let's use a height of (68+e) and see what that does to the volume of the box. v = (102-h/2)(102-h/2)h v = (102-(68+e)/2)(102-(68+e)/2)(68+e) v = (102-(34+e/2))(102-(34+e/2))(68+e) v = (68-e/2)(68-e/2)(68+e) v = (4624 - 34e - 34 e + 0.25e^2)(68+e) v = (4624 - 68e + 0.25e^2)(68+e) v = 314432 - 4624e + 17e^2 + 4624e - 68e^2 + 0.25 e^3 v = 314432 - 51e^2 + 0.25e^3 Now look at the 2 terms that use e. The -51e^2 term will always be negative, but the +0.25e^3 term will be negative if e is negative and positive if e is positive. So a positive e value (e.g. Make the height larger) does have a possibility of increasing the volume if it can overcome the -51e^2 term. So let's make that equation 0 < -51e^2 + 0.25e^3 51e^2 < 0.25e^3 51 < 0.25e 204 < e So if we make the height 68 + 204 = 272, then we could have a box with a larger volume. But that's impossible since the largest measurement for any edge is 204 and that's assuming you're willing to set the length of the other 2 dimensions to 0.</span>
5 0
3 years ago
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