We have two numbers say a, b. And a system of equations.

It looks a bit intimidating but it's actually very easy.
Instead of term a + b in the second equation we can say it's zero because the first equation describes a + b as being equal to 0.
So,

The above equation is not true therefore numbers a and b do not exists in the real number domain.

No solution.
Hope this helps.
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8:30 am. A quarter of an hour is 15 min
Answer:
184.
Step-by-step explanation:
p(x) = 2x^4 + 6x^3 - 3x^2 + 24
Whet x = 2:
p(2) = 2(2)^4 + 6(2)^3 - 3(2)^2 + 24
= 2*16 + 6*8 - 3*4 + 24
= 32 + 48 - 12 + 24
= 92.
Together they spent 184.