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3 years ago

Sistemas de ecuaciones

Mathematics

1 answer:

kolezko [41]3 years ago

6 0

Answer:

El Dr. Potter aplicó 32 vacunas de polio y 28 de sarampión.

Step-by-step explanation:

- First, the data must be taken into account to create the equations:

X + Y = 60; (Equation 1)

- Where:

X = Number of polio vaccines and Y = Number of measles vaccines.

4X + 2Y = 184; (Equation 2)

Where for each polio vaccine there are 4 doses and for each measles vaccine there are 2 doses.

- We clear the variable that we want to find in each equation:

Y = 60 - X; (And we call it equation 3)

Y = (184-4X) / 2; (And we call it equation 4)

- Now both equations are equalized in terms of the same variable:

60 - X = (184 - 4X) / 2

- Then X is cleared to find its value:

120 - 2X = 184 - 4X

4X - 2X = 184 - 120

2X = 64

X = 32

- Now we demonstrate the value of X obtained in equation 1 or 2 to give the values of Y

(32) + Y = 60

Y = 60 - 32

Y = 28

- Finally, both values are used to see if equation 2 gives us the correct data:

4 (32) + 2 (28) = 184

128 + 56 = 184

- The answer is given:

Dr. Potter gave 32 polio and 28 measles vaccines.

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The pucks used by the National Hockey League for ice hockey must weigh between and ounces. Suppose the weights of pucks produced

Dahasolnce [82]

Answer:

$P(5.5$

And we can find this probability using the normal standard distribution or excel and we got:

$P(-2.769$

Step-by-step explanation:

For this case we assume the following complete question: "The pucks used by the National Hockey League for ice hockey must weigh between 5.5 and 6 ounces. Suppose the weights of pucks produced at a factory are normally distributed with a mean of 5.86 ounces and a standard deviation of 0.13ounces. What percentage of the pucks produced at this factory cannot be used by the National Hockey League? Round your answer to two decimal places. "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(5.86,0.13)$

Where $\mu=5.86$ and $\sigma=0.13$

We are interested on this probability

$P(5.5$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(5.5$

And we can find this probability using the normal standard distribution or excel and we got:

$P(-2.769$

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AnnZ [28]

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3 years ago

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3 years ago

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3 years ago

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sasho [114]

Answer:

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3 years ago