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katen-ka-za [31]
3 years ago
13

Which table shows a no change linear relationship?

Mathematics
2 answers:
Phantasy [73]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Each of the tables is a linear relationship. Linear relationships increase or decrease steadily by adding or subtracting a constant. Table A increases by 5. Table B decreases by 2. Table C doesn't change. Table D increase by 4.

A "no change" means the y values never change. The constant is 0 and is a horizontal line. Table C is the solution.

Fudgin [204]3 years ago
3 0

Answer:

Option C.

Step-by-step explanation:

Linear relationship : If the relation between variables is represent by a non vertical straight line, then it is called a  linear relationship.

Horizontal line is a special case of linear relationship. It is know as no change linear relationship. It means the output value remains same for each input value.

In option C, the given table is  

x      y

14    12

20   12

26   12

32   12  

Only in option C, the y-values are constant. So, it represents no change linear relationship.

Therefore the correct option is C.

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180

Step-by-step explanation:

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Cross multiply:
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the perimeter of a basketball court is 102 meters, and length is 6 meters longer than twice the width, what r length and width.
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Thus,

102 = 2(l + w)

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25-42 Differentiate the function.<br> 25. <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B5%7D%2B5%5E%7Bx%7D" id="TexFormula
natulia [17]

Answer:

<u>y'= 5x^4 + 5^x In(5)</u>

Step-by-step explanation:

<u>Differentiate</u><u> </u><u>with </u><u>Respect</u><u> </u><u>to</u><u> </u><u>x</u>

<u>f(</u><u>x)</u><u>'</u><u>=</u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>In(</u><u>5</u><u>^</u><u>x</u><u>)</u>

<u>f(</u><u>x)</u><u>'</u><u>=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>x </u><u>In(</u><u>5</u><u>)</u>

<u>with </u><u>respect</u><u> </u><u>to </u><u>x,</u><u> </u><u>we </u><u>have</u>

<u>y'=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>y </u><u>In(</u><u>5</u><u>)</u>

<u>y'=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>5</u><u>^</u><u>x</u><u> </u><u>In(</u><u>5</u><u>)</u>

8 0
2 years ago
Can anyone help with this. Will give you all my points and brainliest:)
Nana76 [90]

Answer:3. 4:8

4. 1:4

Step-by-step explanation:

5. 48

6. 3

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3 years ago
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