I need all parts answered please!

Mathematics

1 answer:

Arisa [49]3 years ago

5 0

Width = w
d)length in term of width
w + 5
b)
2(w + w + 5) > 30
2(2w +5)>30

c)
solve
2(2w +5) > 30
4w + 10 > 30
4w > 20
w > 5

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Algebra help

Vilka [71]

To determine the correct ordered pairs which will agree with the function, we can substitute values to the function and see whether it agree with each other. We do as follows:

(0,1)
 f(x)=128(0.5)^0
 f(x)=128

(1,64)
 f(x)=128(0.5)^1
f(x) = 64 <--------CORRECT ANSWER

(3,16)
 f(x)=128(0.5)^3
f(x) = 16 <--------CORRECT ANSWER

(8,0.5)
 f(x)=128(0.5)^8
f(x) = 1/2

Hope this answers the question. Have a nice day.

5 0

3 years ago

Does anyone whatsoever have any tips for coordinate plane- like I need alot please. anything you know that helps u.

Anon25 [30]

Most of the time for coordinate planes, they are asking you to plot the point correctly, and to state which quadrant the point falls into.

The Quadrant points start at (+ , +) for Quadrant I, and moves clockwise. See attached picture.

Quadrant I: (+ , +)

Quadrant II: (+ , -)

Quadrant III: (- , -)

Quadrant IV: (- , +)

Remember, the point is split into two parts, in which the first one is x (which signifies the placement for the horizontal line), while the other is y (which signifies the placement for the vertical line).

7 0

3 years ago

Read 2 more answers

Solve the equation 6w2 – 7w – 20 = 0.

azamat

For this case we have the following quadratic equation:

$6w ^ 2-7w-20 = 0$

Where:

$a = 6\\b = -7\\c = -20$

Its roots will be given by:

$w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}$

The roots are:

$w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}$