Question

Determine the intercepts of the line y+1=3(x-4)

Answer 1

Answer:

x-intercept = $\frac{13}{3}$

y-intercept = $-13$

Step-by-step explanation:

We are given the following equation of a line and we are to find the x and y intercepts for it:

$y + 1 = 3 ( x - 4 )$

To find the x-intercept, we will put in 0 for the y to get:

$0 + 1 = 3 ( x - 4 ) \\\\ 1 = 3 x - 12 \\\\ 3 x = 1 + 12 \\\\ x = \frac { 13 } { 3 }$

To find the y-intercept, we will put in 0 for the x to get:

$y + 1 = 3 ( 0 - 4 ) \\\\ y + 1 = -124 \\\\ y = - 12 - 1 \\\\ y = - 13$

So the x-intercept is $\frac{13}{3}$ while the y-intercept is $-13$.

Answer 2

To find the intercepts, the other number will be 0 (x-intercept: when y is 0, and vise-versa).

So:

x-intercept: 0 + 1 = 3x - 12 -> 3x = 13 -> x = 13/3, so it will be ($\frac{13}{3}$, 0).

y-intercept: y + 1 = 3*0 - 12 -> y = -13, so it will be (0, -13).