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Usimov [2.4K]
3 years ago
15

I am greater than 4 tens and less than 5 tens I have 9 ones

Mathematics
1 answer:
aliina [53]3 years ago
4 0

4 tens = 40 and 5 tens = 50 … therefore the number has to be between 40 and 50

So: 40 < x <50 … this says that x is greater than 40 and less than 50

 

So the possible numbers would be: 41,42,43,44,45,46,47,48,49

Now the number must have 9 ones … which mean the only number would be 49

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seropon [69]

Answer:

.66 cu. meters

Step-by-step explanation:

volume for cone is V=1/3 x TT x r^2 x height

TT (pi) is 3.14

radius is 1/2 of diameter (1/2 x 1.5 =  .75 )

height is 1.5 x radius (1.5 x .75 = 1.125)

V= 1/3 x 3.14 x .75^2 x 1.125

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2 years ago
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8 0
3 years ago
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Can someone help? It’s about 2 column proofs
Gwar [14]

Step-by-step explanation:

1. AB = BC (B is the midpoint of AC)

2. DE = EF (E is the midpoint of DF)

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5. ΔDEB ≅ ΔFEB (RHS)

6. DB = FB (corresponding ∠s of ≅ Δs)

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4 0
2 years ago
Inventory Heung-Soo is responsible for checking a shipment of technology equipment that contains laser printers that cost $700 e
Alla [95]

Answer:

P + M = 30

700P + 200M = 15000

Number of laser printers = 18

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Step-by-step explanation:

Let P = number of laser printers

Let M = number of color monitors

Given total number of boxes = 30

⇒ P + M = 30

Given:

  • $700 = cost of laser printer
  • $200 = cost of color monitor
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⇒ 700P + 200M = 15000

Rewrite P + M = 30 to make P the subject:

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Substitute into 700P + 200M = 15000 and solve for M:

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⇒ 500M = 6000

⇒ M = 12

Substitute found value for M into P = 30 - M and solve for P:

⇒ P = 30 - 12 = 18

5 0
2 years ago
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Answer: You can multiply the numerator and the denominator by 2.

Step-by-step explanation:

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To find an equivalent fraction of a determined fraction, you need to multiply the numerator and the denominator by the same number.

Knowing the fraction \frac{1}{4}, where the numerator is 1 and the denominator is 4, you can multiply each one (the numerator and the denominator) by 2 to obtain an equivalent fraction.

Then:

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5 0
3 years ago
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