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2 years ago

Evaluate the expresion 27+6x2+3/6

Mathematics

1 answer:

SSSSS [86.1K]2 years ago

5 0

Exact Form: $\frac{79}{2}$

Decimal Form: 39.5

Mixed Number Form: 39 $\frac{1}{2}$

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For f(x)=-2x^3-4x^2+3x-8 , use the remainder theorem to determine f(-1).

konstantin123 [22]

Answer:

- 13

Step-by-step explanation:

Substitute x = - 1 into f(x) to obtain the remainder on dividing by (x + 1)

f(- 1) = - 2(- 1)³ - 4(- 1)² + 3(- 1) - 8

= 2 - 4 - 3 - 8 = - 13

Thus the remainder on dividing f(x) by (x + 1) is - 13

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3 years ago

Read 2 more answers

Maggie has $14,100 to invest, and wishes to gain $4,000 in interest over the next eight years. Approximately what is the minimum

julsineya [31]

Simple interest doesn't compound, so we just find the interest she needs by dividing 4,000 by 8, and then divide that number by her principal to find the rate of interest.

4,000 ÷ 8 = 500
She needs 500 dollars per year in interest.

800 ÷ 14,100 = .0355 = 3.55%

Answer is B

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3 years ago

A recliner that costs $150 was marked up by 100%.

sveta [45]

Recliner:
Markup $10
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computer:
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3 years ago

I need to use the Pythagorean Theorem to find X. I don’t know how to do that!!

frutty [35]

Answer:

17) x=8

18) $x=\sqrt{189}$ or $x= 3\sqrt{21}$

Step-by-step explanation:

So the rule is $a^{2} +b^{2} =c^{2}$ , "c" being the hypothenuse, or the long line that is opposite to the right angle.

17) We know that both values of x are equal to each other, which makes everything 10x easier!

$x^{2} +x^{2} =(8\sqrt{2}) ^{2}$

(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)

<em>simplify</em> (╥︣﹏╥)

$2x^2=8^2(\sqrt{2} )^{2}$

$2x^2=64(2)$

$2x^2=128$

$x^{2}= 128/2$

$x^{2} =64$

x=8

18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)

Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!

$c^{2} - b^{2} = a^{2}$