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Whitepunk [10]
2 years ago
6

Evaluate the expresion 27+6x2+3/6

Mathematics
1 answer:
SSSSS [86.1K]2 years ago
5 0
Exact Form: \frac{79}{2}


Decimal Form: 39.5


Mixed Number Form: 39\frac{1}{2}
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Answer:

Step-by-step explanation:

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Country and Jazz

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Let f(x)=(x-2)^3+8 Find the inverse of f(x). Please show steps in written form would be gladly appreciated
Tatiana [17]

Hello from MrBillDoesMath!

Answer:

(x-8)^(1/3) +2

Discussion:

To find the inverse of a function swap the values of x and y in the original equation y = (x-2)^3 +8  and solve for y.

y = (x-2)^3 +8          =>  original function. swap x and y values

x = (y-2)^3 + 8        =>  subtract 8 from both sides

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(x-8)^(1/3) +2 = y      => y is the inverse



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4 0
3 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

7 0
2 years ago
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Find the mean of the following data set.<br> 42, 45, 58, 63<br> 42<br> 47<br> 52
igomit [66]
52 i believe.

42 + 45 + 58 + 63 = 208
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