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g100num [7]
3 years ago
12

Lowest common denominator then add

Mathematics
1 answer:
ad-work [718]3 years ago
6 0

Answer: Is there an equation that goes with this?

Step-by-step explanation:

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The ages of the members of a volunteer group are shown below.
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I think it’s D

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SoIve the system of equations by elimination. (Addition)<br> 1)-2x + 4y = -22<br> 2x + 8y = –26
Rufina [12.5K]

Answee:

We have these two equations:

-2x +4y =-22

2x + 8y -26

We need to try to get the same number multiplying both x or y, I think we can make the 2 of the first equation negative, for that, we multiply all the equation by -1:

2x + 8y =-26  ---- -2x - 8y =26

Now we have this:

-2x +4y = -22

-2x -8y = 26

Now e substract both equations:

-2x - (-2x) +4y -(-8y) = -22-26

12y = -48

Y = -48/12 = -4

And we replace to get x

-2x + 4y = -22

-2x +4*(-4)=-22

-2x - 16 = -22

x= -6/-2 =3

6 0
3 years ago
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What does 70.2 rounded to the nearest ten?
a_sh-v [17]

Answer:

70

Step-by-step explanation:

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If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo
Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or,          Q = 40 kg × 4200 × 18

or,           Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule    

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

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What is a line graph?
scZoUnD [109]
A line graph, or line chart, shows info as a series of data points that are connected by line segments.
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4 years ago
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