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3 years ago

2/5 of 40 in fractional parts

Mathematics

2 answers:

Romashka [77]3 years ago

7 0

Dividing 40 into fifths...
40 ÷ 5 = 8

Since 1/5 of 40 is 8, 2/5 of 40 is 16.

Sati [7]3 years ago

5 0

2 2
--- x 40 = ---- x 8 = 16
5 1

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If four blue marbles and eight non-blue marbles make a probability of 0.33, how many non-blue marbles do you need to combine wit

den301095 [7]

The number of non-blue marbles you need to combine with the blue marbles to achieve a probability of 0.1 is 28.

<h3>How many non-blue marbles are needed?</h3>

Probability determines the odds that a random event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The more likely the event is to happen, the closer the probability value would be to 1. The less likely it is for the event not to happen, the closer the probability value would be to zero.

Probability of picking a blue marble = number of blue marble / total number of marbles

4 / (4 + 8)

4/12 = 0.33

The number of non-blue marbles needed = ( 4 / 0.1) - 12

40 - 12 = 28

To learn more about probability, please check: brainly.com/question/13234031

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5 0

1 year ago

Evaluate a+b for a=-17 and b=8

In-s [12.5K]

substitute 17 for A

substitute 8 for B

should look like this

17+8

then add

should look like this

17+8=25

8 0

2 years ago

Show by substitution whether the number r is a solution of the corresponding quadratic equation.

Stels [109]

Answer:

It's choice B.

Step-by-step explanation:

When r= -11,

x^2 + 8x - 33 = (-11)^2 - 88 - 33

= 121 - 88 - 33

= 0

- so x = -11 gives a zero value and is a solution to the equation.

3 0

1 year ago

PLEASE HELP!!!!!!!!!!!!!!!!!!

N76 [4]

Answer:

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7 0

2 years ago

What is the solution of √x-5 = x-11

PIT_PIT [208]

Hey!

To solve x in this equation we must first add five to both sides to get $\sqrt{x}$ on its own.

Original Equation :
$\sqrt{x} - 5 = x - 11$

New Equation {Added 5 to Both Sides} :
$\sqrt{x} =x-6$

Now we must square both sides of the equation.

Old Equation :
$\sqrt{x} =x-6$

New Equation {Changed by Squaring Both Sides} :
$x= x^{2} -12x+36$

And now we must solve the new equation.

Step 1 - Switch sides
$x^{2} -12x+36=x$

Step 2 - Subtract x from both sides
$x^{2} -12x+36-x=x-x$

Step 3 - Simplify
$x^{2} -13x+36=0$

Now we need to solve the rest of the equation using the quadratic formula.

$\frac{-(-13)+ \sqrt{(-13) ^{2}-4*1*36 } }{2*1}$

${13+ \sqrt{(-13)^{2}-4*1*36 }=13+ \sqrt{25}$

$\frac{13+ \sqrt{25}}{2}$

$\sqrt{25}=5$

$\frac{13+5}{2}$

$\frac{18}{2}$

9

$\frac{-(-13)- \sqrt{(-13) ^{2} -4*1*36} }{2*1}$

4

So, this means that in the equation $\sqrt{x} -5=x-11$ , x = 9 and x = 4.

Hope this helps!

- Lindsey Frazier ♥

4 0

2 years ago