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melomori [17]
3 years ago
15

If you wanted to combine equal numbers of Na and Cl atoms in a flask, how much Cl would you have to add if you added 23g of NA?

Biology
1 answer:
Gwar [14]3 years ago
5 0

<u>Answer:</u> The mass of chlorine atom required to combine is 35.5 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For sodium:</u>

Given mass of sodium = 23 g

Molar mass of sodium = 23 g/mol

Putting values in equation 1, we get:

\text{Moles of sodium}=\frac{23g}{23g/mol}=1mol

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles

So, 1 mole of sodium will contain = (1\times 6.022\times 10^{23})=6.022\times 10^{23} number of atoms

Number of atoms of chlorine = Number of atoms of sodium = 6.022\times 10^{23} = 1 mole

Now, calculating the mass of chlorine required by using equation 1:

Moles of chlorine = 1 mole

Molar mass of chlorine = 35.5 g/mol

Putting values in equation 1, we get:

1mol=\frac{\text{Mass of chlorine}}{35.5g/mol}\\\\\text{Mass of chlorine}=(1mol\times 35.5g/mol)=35.5g

Hence, the mass of chlorine atom required to combine is 35.5 grams.

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