Question

If you wanted to combine equal numbers of Na and Cl atoms in a flask, how much Cl would you have to add if you added 23g of NA?

Answer 1

Answer: The mass of chlorine atom required to combine is 35.5 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$      .....(1)

• For sodium:

Given mass of sodium = 23 g

Molar mass of sodium = 23 g/mol

Putting values in equation 1, we get:

$\text{Moles of sodium}=\frac{23g}{23g/mol}=1mol$

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles

So, 1 mole of sodium will contain = $(1\times 6.022\times 10^{23})=6.022\times 10^{23}$ number of atoms

Number of atoms of chlorine = Number of atoms of sodium = $6.022\times 10^{23}$ = 1 mole

Now, calculating the mass of chlorine required by using equation 1:

Moles of chlorine = 1 mole

Molar mass of chlorine = 35.5 g/mol

Putting values in equation 1, we get:

$1mol=\frac{\text{Mass of chlorine}}{35.5g/mol}\\\\\text{Mass of chlorine}=(1mol\times 35.5g/mol)=35.5g$

Hence, the mass of chlorine atom required to combine is 35.5 grams.