A remote ranch has a cylindrical water storage tank. It has a vertical central axis, a diameter of 16 ft, the sides are 5 ft hig
h, and it is full to the brim. The depth of this water is 4 ft. How much work (in ft-lb) would be required to pump all of the water over the upper rim? (Use the fact that water weighs 62.5 lb/ft3. Round your answer to the nearest integer.)
1 answer:
Answer and Step-by-step explanation:
Given: diameter = 16ft height = 5 ft. Depth = 4ft
Work =?
As we know that work = force x distance
W= distance x density x volume
W= ʃ04 (5-y) 62.5x ∏ (d/2)2dy (area = ∏r2 , r= d/2)
= 62.5 ʃ04 (5-y) ∏ (4y) dy
=62.5∏ ʃ04 (5-y) 4ydy
=62.5∏ ʃ04 20y-4y2dy
=62.5∏ |20y2/2 – 4y3/3|04
=62.5∏ |74.66|
=14659ft.lbs (approximately)
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