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2 years ago

X1 − x2 + x3 = 6

Mathematics

1 answer:

mariarad [96]2 years ago

7 0

I feel like it’s 6 but i May be wrong

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See image. I only have an hour. Thank you!

Readme [11.4K]

Step-by-step explanation:

${2.7}^{12.2} = (5x + 9) \\ 5x = 183069.7433 \\ x = 36613.95$

8 0

2 years ago

I need help what is this?

zhuklara [117]

Answer:

picture from Goldbach's conjecture.

Step-by-step explanation:

Goldbach's conjecture is one of the oldest and best-known unsolved problems in number theory and all of mathematics. It states:

Every even integer greater than 2 is the sum of two primes.

The conjecture has been shown to hold for all integers less than 4 × 10^18, but remains unproven despite considerable effort.

So on the red and blue axes you see primes. The list of black numbers are even numbers.

8 0

2 years ago

What is the first step in determining if 6 is a solution to 3 x = 18?

andreev551 [17]

Answer:

Step-by-step explanation:I think it's C :)

6 0

2 years ago

Read 2 more answers

The value 3.84 is 12% of what number?

xeze [42]

So percent means parts out of 100
so 12%=12/100=1.2/10=0.12/1=0.12

3.84 is 12% of what
'of' means multiply
'is' means = sign

therefor
3.84=0.12 times what
divide both sides by 0.12
32=what

th enumber is 32

7 0

3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

2 years ago