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irga5000 [103]
3 years ago
8

Solve the equation sqrt x+3+4 =5 for the variable. Show each step of your solution process.

Mathematics
1 answer:
Keith_Richards [23]3 years ago
3 0

Domain:\\x+3\geq0\to x\geq-3\\\\\sqrt{x+3}+4=5\ \ \ \ |-4\\\\\sqrt{x+3}=1\ \ \ |^2\\\\(\sqrt{x+3})^2=\pm1^2\\\\x+3=\pm1\ \ \ \ |-3\\\\x=-4\notin D\ \vee\ x=-2\in D\\\\Answer:\ \boxed{x=-2}

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Answer:

  1. b = 15
  2. c = 51
  3. c = 100
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Step-by-step explanation:

Using the Pythagoras theorem equation:

c^{2}=a^{2}+b^{2}

Where 'c' is the hypotenuse and 'b' and 'a' the sides of the right triangle.

1) Here c = 17, a = 8 and b = ?

Then, using the above equation we can find the side b.

17^{2}=8^{2}+b^{2}

b=\sqrt{225}

b=15

2) Here a = 24, b = 45 and c = ?  

c=\sqrt{24^{2}+45^{2}}

c=51

3)  Here a = 28, b = 96 and c = ?

c=\sqrt{28^{2}+96^{2}}    

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4)  Here a = 17, b = ? and c = 28

b=\sqrt{28^{2}-11^{2}}  

b=25.75

Just in the 4 case x is an altitude.

I hope it helps you!

         

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