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Zepler [3.9K]
4 years ago
5

A building makes a 90° angle with the ground. A ladder leans against the building, making a 110° exterior angle with the ground.

What are the measures of the two interior angles?
Mathematics
1 answer:
liberstina [14]4 years ago
7 0

<u>Answer:</u>

A building makes a 90^{\circ} angle with the ground .The two interior angles are 70^{\circ} and 20^{\circ}

<u>Solution: </u>

Given, a ladder which is against the building wall makes an exterior angle of 110^{\circ}

And building makes a  90^{\circ} angle with the ground.

So, altogether it makes a right angle triangle with ladder as hypotenuse and ground as base leg and building as another leg.  

Now, we know that, sum of exterior angles and interior angles equals to 180^{\circ}

Here, in the case of ground and ladder, exterior angle is 110^{\circ} and interior angle is unknown.

Exterior angle + interior angle = 180

110 + interior angle = 180

Interior angle = 180 – 110

Interior angle = 70^{\circ}

We have found one of the two interior angles of right angle triangle.

We know that, sum of angles in a triangle is 180 degree

Known Interior angle + unknown interior angle + right angle = 180

70 + unknown interior angle + 90 = 180

Unknown interior angle + 160 = 180

Unknown interior angle = 180 - 160

Unknown interior angle = 20^{\circ}

Hence the two interior angles are  70^{\circ} and 20^{\circ}

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Eight rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other ro
Brums [2.3K]

Answer:

9.11*10^-4 %

Step-by-step explanation:

To find the probability, you simply need to find the possible outcomes that allows no rooks to be in danger, and the possible amount of ways to place the rooks.

For the first outcome, you start by putting 1 rook in the first columns, you have 8 possible rows to do this. The next rook in the next column will only have 7 possible rows, as you have to exclude the one where the previous rook is located. The next rook, 6 possibilities, the next 5, and so on. So we conclude that the total amount of ways so that none of the rooks can capture any of the other rooks is 8*7*6*5*4*3*2*1 = 8! = 40320

In order to find the total amount of ways to place the rooks, you can just use a combinatoric:

\left[\begin{array}{ccc}64\\8\end{array}\right]= \frac{64!}{8!(64-8)!} = 4.43*10^9

Then:

P = \frac{40320}{4.43*10^9}*100\%=9.11*10^{-4}\%

5 0
3 years ago
Find the miing value in the ratio table. Then write the equivalent ratio. Plum 14 42 Grape 7 3 24 The equivalent ratio are 14 :
denis-greek [22]

The equivalent ratio is 8 : 4.

And the missing values are as follows 21, 6 and 48.

Complete table be,

Plum     14   42   6   48

Grape    7    21    3    24

Given, a ratio table

Plum     14   42   __   __

Grape    7    __    3    24

we have to find the missing values and the equivalent ratios.

in the first ratio,

Plum : Grape = 14 : 7 = 2 : 1

Now, in the second ratio,

2 : 1 = 42 : __

x = 21

Now, in the third ratio,

2 : 1 = __ : 3

x = 6

Now, in the forth ratio,

2 : 1 = __ : 24

x = 48

So, the equivalent ratio is 8 : 4.

And the missing values are as follows 21, 6 and 48.

Hence, the equivalent ratio is 8 : 4.

And the missing values are as follows 21, 6 and 48.

Complete table be,

Plum     14   42   6   48

Grape    7    21    3    24

Learn more about Ratios and Proportions here brainly.com/question/26974513

#SPJ4

4 0
1 year ago
1 2/3 times 3 2/3 greater than 3 2/3
jek_recluse [69]
Yes, yes it is :)
your welcome 
3 0
4 years ago
Help me on this I really need it
CaHeK987 [17]

Answer:


Step-by-step explanation:

Given that sale of grills increase 6% per year

CUrrent sale of grills this year = 3300

So in the first year sales would increase by 3300(6%)

Total sales in the I year =3300+3300(6%)

This will be again increasing by 6% in II year and so on.

Hence we have

every year 3300 increases by 6% compoundly

So

No of sales in t year

=3300(1+0.06)^t\\=3300(1.06^t)

In 6th year sale

s(6) =3300(1.06)^6\\=4681.11

7 0
3 years ago
write and solve an equation to show thw average number of calendars her 3rd period class sold peer week during the four week cha
kari74 [83]
If they sold 89 calendars over 4 weeks, the 'equation' would look like (x = average calendars sold over 4 weeks):
x =  \frac{89}{4}

If you solve it, you get:
22 \frac{1}{4}

Which is equal to 22.25. Hope this helps!
5 0
3 years ago
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