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Zepler [3.9K]
3 years ago
5

A building makes a 90° angle with the ground. A ladder leans against the building, making a 110° exterior angle with the ground.

What are the measures of the two interior angles?
Mathematics
1 answer:
liberstina [14]3 years ago
7 0

<u>Answer:</u>

A building makes a 90^{\circ} angle with the ground .The two interior angles are 70^{\circ} and 20^{\circ}

<u>Solution: </u>

Given, a ladder which is against the building wall makes an exterior angle of 110^{\circ}

And building makes a  90^{\circ} angle with the ground.

So, altogether it makes a right angle triangle with ladder as hypotenuse and ground as base leg and building as another leg.  

Now, we know that, sum of exterior angles and interior angles equals to 180^{\circ}

Here, in the case of ground and ladder, exterior angle is 110^{\circ} and interior angle is unknown.

Exterior angle + interior angle = 180

110 + interior angle = 180

Interior angle = 180 – 110

Interior angle = 70^{\circ}

We have found one of the two interior angles of right angle triangle.

We know that, sum of angles in a triangle is 180 degree

Known Interior angle + unknown interior angle + right angle = 180

70 + unknown interior angle + 90 = 180

Unknown interior angle + 160 = 180

Unknown interior angle = 180 - 160

Unknown interior angle = 20^{\circ}

Hence the two interior angles are  70^{\circ} and 20^{\circ}

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Answer:

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Step-by-step explanation:

Let the length of the rectangular exercise run = l ft

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Sinoman has to cover a rectangular exercise run from three sides with the fencing material,

So length of the material = (l + 2w) ft

l + 2w = 100

l = 100 - 2w --------(1)

Area of the rectangular area covered = Length × width

A = lw

A = w(100 - 2w)    [(l = 100 - 2w)from equation (1)

For maximum area we find the derivative of area and equate it to zero.

\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]

A'=\frac{d}{dw}(100w-2w^{2} )

A' = 100 - 4w

For A' = 0

100 - 4w = 0

4w = 100

w = 25 ft

From equation (1)

l = 100 - 2w

l = 100 - 2×(25)

l = 50 ft

Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.

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Answer:

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Answer:

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Step-by-step explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

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Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;

a\ \alpha\ \frac{1}{m}

Convert variation to equality

a = \frac{F}{m}; Where F is the constant of variation (Force)

Make F the subject of formula;

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