Part B: How many children chose not to sign up for swimming or canoeing?

There are 4 different magazines on Hannah's nightstand. Each

Lady_Fox [76]

Answer:

I need the answer did you get it

Step-by-step explanation:

6 0

2 years ago

An equilateral is shown inside a square inside a regular pentagon inside a regular hexagon. The square and regular hexagon are s

Kay [80]

Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle. This can be obtained by finding each shaded area and then adding them.

<h3>Find the expression for the area of the shaded regions:</h3>

From the question we can say that the Hexagon has three shapes inside it,

Pentagon

Square

Triangle

Also it is given that,

An equilateral triangle is shown inside a square inside a regular pentagon inside a regular hexagon.

From this we know that equilateral triangle is the smallest, then square, then regular pentagon and then a regular hexagon.

A pentagon is shown inside a regular hexagon.

Area of first shaded region = Area of the hexagon - Area of pentagon

An equilateral triangle is shown inside a square.

Area of second shaded region = Area of the square - Area of equilateral triangle

The expression for total shaded region would be written as,

Shaded area = Area of first shaded region + Area of second shaded region

Hence,

⇒ Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle.

Learn more about area of a shape here:

brainly.com/question/16501078

#SPJ1

8 0

1 year ago

Read 2 more answers

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

$\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666$

Second step. <u>Calculate the standard deviation</u>

$\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}$

$\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}$

$\sigma=\sqrt{17.815}=4.22$

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

$\bar X \pm t\frac{\sigma}{\sqrt n}$

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0

2 years ago

8x-6y=54 in slope intercept form please!!

NikAS [45]

Answer: y= 4/3x-9

Step-by-step explanation:

4 0

3 years ago

A jar contains 18 red marbles 14 green marbels and 20 blue marbles a marble was selected at random the color was recorded and th

muminat

The "relative frequency" is

(number of times a blue marble came out)
divided by
(total number of trials before everybody got bored and quit) .

-- The relative frequency of blue was (20/60) = (33 and 1/3) % .
(Even though 38.5% of the marbles in the jar are blue,
they didn't get picked that often.)

-- The relative frequency of green was (18/60) = 30 % .
(Even though only 26.9% of the marbles in the jar are green,
they got picked more often than that.)

-- The relative frequency of red was (22/60) = (36 and 2/3) % .
(Even though 42.3% of the marbles in the jar are red,
they didn't get picked that often.)

3 0

3 years ago