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kiruha [24]
2 years ago
10

John spent 30 minutes developing an estimate for a job. The job itself took 2 hours, 45 minutes to

Mathematics
1 answer:
kicyunya [14]2 years ago
6 0

Answer:

Ratio is 11 : 13

Step-by-step explanation:

We are given;

Time to develop estimate = 30 minutes

Time to do the job = 2 hours 45 minutes = (2 * 60) + 45 = 165 minutes

Total time to develop and do job = 165 + 30 = 195 minutes

Thus;

Ratio of time spent on job to total time = 165 : 195

Whrn this is broken further, we have; 11 : 13

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Please help with this ASAP
uranmaximum [27]

Answer:

7w^3/5v

Step-by-step explanation:

42v^3w^4/30v^4w

42 = 6 * 7

30 = 6*5 , factor

6*7v^3w^4/6*5v^4w

6 is common, cancel

7v^3w^4/5v^4w

simplify w^4/w = w^3

v^3/v^4 = 1/v

therefore, 7w^3/5v is the answer

7 0
3 years ago
How do I solve this problem?
ddd [48]

Answer:

\frac{8}{12}

I hope this helps you...

6 0
3 years ago
WILL GIVE A BRAINLEST !!!
LiRa [457]
The following were used:Convenience,Systematic and Voluntary.
4 0
3 years ago
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Can someone please answer this???? ASAP
timofeeve [1]

Answer:

A. y=-\dfrac{8}{7}x-\dfrac{18}{7}

Step-by-step explanation:

Let y=mx+b be the equation of the perpendicular line.

Two perpendicular lines have slopes with product equal to -1. The slope of the given line is \frac{7}{8} Hence,

\dfrac{7}{8}\cdot m=-1\\ \\m=-\dfrac{8}{7}

is the slope of needed line.

This line passes through the point (-4,2), so its coordinates satisfy the equation:

2=-\dfrac{8}{7}\cdot (-4)+b\\ \\b=2-\dfrac{32}{7}=-\dfrac{18}{7}

Therefore, the equation of the line is

y=-\dfrac{8}{7}x-\dfrac{18}{7}

7 0
3 years ago
If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, what is the acceleration of the objec
SVETLANKA909090 [29]

Answer

Find out the what is the acceleration of the object .

To prove

Formula

Acceleration = \frac{Final\ velocity - Intial\ velocity}{Time }

Where

t = the time in which the change occurs

As given

If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s .

Final velocity = 98 m/s  

Intial velocity = 65 m/s

Time = 12 s

Put in the formula

Acceleration = \frac{98 - 65}{12}

Acceleration = \frac{33}{12}

Acceleration = 2 .75 m/s ²

Option (A) is correct .




7 0
3 years ago
Read 2 more answers
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