So let's start from the beginning.
Add 2 and 4:
(2 + 4)
Multiply the sum by 3:
3(2 + 4)
Then add 5 to that product:
3(2 + 4) + 5
Then double the results:
2[3(2 + 4) + 5]
Answer: Y=2/3x+4 that’s your rule/equation
Answer:
Example:
A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.
a) Construct a probability tree of the problem.
b) Calculate the probability that Paul picks:
i) two black balls
ii) a black ball in his second draw
Solution:
tree diagram
a) Check that the probabilities in the last column add up to 1.
b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.
ii) There are two outcomes where the second ball can be black.
Either (B, B) or (W, B)
From the probability tree diagram, we get:
P(second ball black)
= P(B, B) or P(W, B)
= P(B, B) + P(W, B)
Answer:
9 boxes
Step-by-step explanation:
Since 1 ft= 12 inches then with diameter of 12 ft, radius becomes 6 ft and converted to inches it's 6*12=72 in
Area of 1 tile= 9*9=81
Number of tiles= 
Number of boxes= 202/25=8.08 boxes hence 9 boxes
Answer:
19000 8000 90000 60000
Step-by-step explanation:
