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3 years ago

Find the value of g(7) for the function below.

Mathematics

1 answer:

Yanka [14]3 years ago

5 0

Answer: The correct answer is (A) - 60/7 :)

Step-by-step explanation: The answer is A because all of the other ones make absolutely no sense one bit at all...!

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For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

Y = -X + 1<br> Y = 3<br> Substitution method

eduard

Answer:

x=-2, y=3. (-2, 3).

Step-by-step explanation:

y=-x+1

y=3

----------

-x+1=3

-x=3-1

-x=2

x=-2

y=-(-2)+1

y=2+1=3

8 0

3 years ago

Two numbers are in the ratio 3:2. if 5 subtracted to each

eduard

Answer:

3 and 2

Step-by-step explanation:

The ratio of the 2 numbers = 3 : 2 = 3x : 2x ( x is a multiple )

When 5 is subtracted from both , that is

3x - 5 : 2x - 5 = 2 : 3

Expressing the ratio in fractional form

$\frac{3x-5}{2x-5}$ = $\frac{2}{3}$ ( cross- multiply )

3(3x - 5) = 2(2x - 5) ← distribute both sides

9x - 15 = 4x - 10 ( subtract 4x from both sides )

5x - 15 = - 10 ( add 15 to both sides )

5x = 5 ( divide both sides by 5 )

x = 1

Thus the 2 numbers are

3x = 3(1) = 3 and 2x = 2(1) = 2

4 0

3 years ago

CAN SOMEONE PLEASE HELP! FOR BRAINLIEST!!!

julsineya [31]

Answer:

3*3*3 first one

Step-by-step explanation:

4 0

3 years ago

|-25.6|+|-11.4| What is the answer to this

12345 [234]

37. The absolute value symbol turns any negative number positive if it's within those brackets, so that's why the answer is positive. Hope this helped!

3 0

2 years ago