On the coordinate grid of a map. Jeff's house is located at (9,5). Hannah's house is at (-5,-5). Kenya's house is located at the
2 answers:
The midpoint formula is 
So just plug in the corresponding coordinates in the correct place to get the midpoint.
x_1=-5 ; x_2=9 ; y_1=-5 ; y_2=5
((-5 + 9)/2 , (-5 + 5)/2)
(4/2 , 0/2)
(2,0) is where Kenya's house is(which is the midpoint).
The distance formula is a bit more complicated than that. The distance formula is D=
In this case now, your looking for the distance from Hannah's house to Kenya's house.
D=
=
=
≈8.6023
So just plug in the corresponding coordinates in the correct place to get the midpoint.
x_1=-5 ; x_2=9 ; y_1=-5 ; y_2=5
((-5 + 9)/2 , (-5 + 5)/2)
(4/2 , 0/2)
(2,0) is where Kenya's house is(which is the midpoint).
The distance formula is a bit more complicated than that. The distance formula is D=
In this case now, your looking for the distance from Hannah's house to Kenya's house.
D=
=
=
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Answer:
Where y is the total amount earned, m the amount for each extended warranty and b the fixed cost and x the total amount of TVs
For this case the value of x = 16 since we have 16 Tvs with extended warranties and we can do this:
and solving for b we got:
And then we can conclude that she earns 60 for each TV
Step-by-step explanation:
For this case we can set a linear model like this:
Where y is the total amount earned, m the amount for each extended warranty and b the fixed cost and x the total amount of TVs
For this case the value of x = 16 since we have 16 Tvs with extended warranties and we can do this:
and solving for b we got:
And then we can conclude that she earns 60 for each TV
Answer:
<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Step-by-step explanation:
Given that:
Number of students who play stringed instruments, N(A) = 15
Number of students who play brass instruments, N(B) = 20
Number of students who play neither, N()' = 5
<u>To find:</u>
The probability that a randomly selected students plays both = ?
<u>Solution:</u>
Total Number of students = N(A)+N(B)+N()' =15 + 20 + 5 = 40
(As there is no student common in both the instruments we can simply add the three values to find the total number of students)
As per the venn diagram, no student plays both the instruments i.e.
Formula for probability of an event E can be observed as:
So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.