If there is 37 cars and 10 are speeding, what percentage of cars is speeding?

Let p be the population proportion for the following condition. Find the point estimates for p and q. In a survey of 1226 adults

weeeeeb [17]

Answer:

(a)0.3303

(b)0.6697

Step-by-step explanation:

Point estimation is the use of sample data to calculate a single value which serves as a best estimate of a given unknown population parameter.

Total Sample=1226

Number who said that they were not confident that the food they eat in country A is safe=405.

The point estimate of those who said that they were not confident that the food they eat in country A is safe is given as $\^{p}$

(a)Point Estimate for p,

$\^{p}=\frac{405}{1226} =0.3303$

(b)Point estimate for q, $\^{q}=$ 1- (point estimate for p)

=1-0.3303

=0.6697

8 0

2 years ago

A trader purchased an article for 250 naira. At what price must he sell to make a profit of 20%?

Misha Larkins [42]

Answer:

300

Step-by-step explanation:

10% of 250 is 25. so 20% is 50

250 + 50 = 300

3 0

2 years ago

Determine whether the situation is linear or nonlinear, and proportional or nonproportional

Arlecino [84]

Answer:

linear and non-proportional

Step-by-step explanation:

When the same amount is added each week, the relationship is linear. When the initial value is 50, not zero, the relationship is non-proportional.

6 0

2 years ago

If (62)x = 1 what is the value of x? Explain your answer.

Alex

Whenever you solve an equation with a single variable you need to isolate the variable by itself on one side of the equal sign. Just be sure that whatever operations you perform on one side you perform on the other sides as well.

62x=1 divide both sides by 62

x=1/62

3 0

2 years ago

An amusement park would like to determine if they want to add in a new roller coaster. In order to decide whether or not they sh

Rzqust [24]

Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 90% confidence level, hence $\alpha = 0.9$ , z is the value of Z that has a p-value of $\frac{1+0.9}{2} = 0.95$ , so the critical value is z = 1.645.