Answer:
See explaination
Explanation:
#Run the code in the python version 3.x.
#Define the function.
def shampoo_instructions(num_cycles):
#Check the cycles to be greater than 1.
if num_cycles < 1:
#Display the statement.
print('Too few.')
#Check the cycles to be greater than 4.
elif num_cycles > 4:
#Display the statement.
print('Too many.')
#The else part.
else:
#Initialize the variable.
N = 1;
#Begin the for loop.
for N in range(N, num_cycles+1):
#Print the result.
print(N , ": Lather and rinse.")
#Print the statement.
print('Done.')
#Call the function.
shampoo_instructions(2)
Answer:
problems or struggles
Explanation:
i believe this because with an effective team most problems aren't there and you can understand and work out problems or struggles
B. training is the correct answer
Answer:
import java.util.Scanner;
public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int inputYear;
boolean isLeapYear;
isLeapYear = false;
inputYear = scnr.nextInt();
// If a year is divisible by 400, then it is a leap year
if (inputYear % 400 == 0)
isLeapYear = true;
// If a year is divisible by 100, then it is not a leap year
if (inputYear % 100 == 0)
isLeapYear = false;
// If a year is divisible by 4, then it is a leap year
if (inputYear % 4 == 0)
isLeapYear = true;
if(isLeapYear)
System.out.println(inputYear + " is a leap year.");
else
System.out.println(inputYear + " is not a leap year.");
}
}
Explanation:
- Take the year as an input from user and store it to inputYear variable.
- If the year is a century year, check if the year is divisible by 400 ( the year must be evenly divisible by 400 ), then set the boolean isLeapYear to true. If a year is divisible by 100, then set the boolean isLeapYear to false. If a year is divisible by 4, then set the boolean isLeapYear to true.
- Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.
Output:
1712
1712 is a leap year.
