Answer:
10
Explanation:
This for-loop is simply iterating three times in which the value of x is being set to the value of x * 1. So let's perform these iterations:
x = 10
When i = 0
x = x * 1 ==> 10
When i = 1
x = x * 1 ==> 10
When i = 2
x = x * 1 ==> 10
And then the for-loop terminates, leaving the value of x as 10.
Hence, the value of x is equal to 10.
Cheers.
Answer:
The left and right index finger
Explanation:
Left index finger: R, T, F, G, C, V
Right index finger: Y, U, H, J, B, N
Answer:
The correct answer is:
"a laser pointer and a remote control"
Explanation:
Let us look at the options one by one.
notes pages and an LCD projector
When she is using these options, she cannot have the freedom to move as she has to operate the projector somehow.
laptop computer and a pointer
In this case she has to operate laptop so movement will be reduced.
<u>A laser pointer and remote control</u> will give her a lot of freedom to move as she can use the remote control to operate the slides and the pointer to point stuff ont the slides.
Hence,
The correct answer is:
"a laser pointer and a remote control"
Matt Pyke and Karsten Schmidt wrote a programming code that created the video which they used for the advertisement for Audi. Thus, Option D is the correct statement.
<h3>What is a
programming code?</h3>
Programming code refers back to the set of instructions, or a system of rules, written in a specific programming language (i.e., the source code).
It is likewise the term used for the source code after it's been processed with the aid of using a compiler and made ready to run on the computer (i.e., the object code).
Therefore, Matt Pyke and Karsten Schmidt wrote a programming code that created the video which they used for the advertisement for Audi. Option D is the correct statement.
Learn more about programming code:
brainly.com/question/25770844
#SPJ1
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
