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posledela
4 years ago
5

11 times as many brushes. If they have 60 brushes altogether?

Mathematics
1 answer:
lesantik [10]4 years ago
3 0
You would do 60 times 11. 60 times 11 equals 660 that is the answer
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An item is regularly priced at $55. Michael bought it on sale for 80% off the regular price. How much did Michael pay
garri49 [273]

Answer:

he paid $11

Step-by-step explanation:

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3 years ago
Please help :) <br> Due asap and thx!
Elenna [48]

Answer:

b . 6 is the length of the hypotenuse

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3 years ago
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It is B that your looking for
5 0
3 years ago
Read 2 more answers
6. A car dealership would like to estimate the mean mpg of its new model car with 90% confidence. The population is normally dis
Yakvenalex [24]

Answer:

92.9997<\mu<99.5203

Step-by-step explanation:

Using the formula for calculating the confidence interval expressed as:

CI = xbar ± Z * S/√n where;

xbar is the sample mean

Z is the z-score at 90% confidence interval

S is the sample standard deviation

n is the sample size

Given parameters

xbar = 96.52

Z at 90% CI = 1.645

S = 10.70.

n = 25

Required

90% confidence interval for the population mean using the sample data.

Substituting the given parameters into the formula, we will have;

CI = 96.52 ± (1.645 * 10.70/√25)

CI = 96.52 ± (1.645 * 10.70/5)

CI = 96.52 ± (1.645 * 2.14)

CI = 96.52 ± (3.5203)

CI = (96.52-3.5203, 96.52+3.5203)

CI = (92.9997, 99.5203)

<em>Hence a 90% confidence interval for the population mean using this sample data is 92.9997<</em>\mu<em><99.5203</em>

4 0
3 years ago
A company makes rubber rafts. 12% of them develop cracks within the first month of operation. 27 new rafts are randomly sampled
rewona [7]

The probability that the number of tested rafts that develop cracks is no more than 3 is <u>.00006</u>.

The true proportion, p for the population is given to 0.12.

Thus, the mean, μ, for the sample = np = 27*0.12 = 3.24.

The sample size, n, given to us is 27.

Thus, the standard deviation, s, for the sample can be calculated using the formula, s = √{p(1 - p)}/n.

s = √{0.12(1 - 0.12)}/27 = √0.003911 = 0.0625389.

We are asked to calculate the probability that the number of tested rafts that develop cracks is no more than 3, that is, we need to calculate P(X ≤3).

P(X ≤ 3)

= P(Z ≤ {(3 - 3.24)/0.0625389) {Using the formula z = (x - μ)/s}

= P(Z ≤ -3.8376114706)

= .00006 {From table}.

Thus, the probability that the number of tested rafts that develop cracks is no more than 3 is <u>.00006</u>.

Learn more about sampling distributions at

brainly.com/question/15507495

#SPJ4

8 0
2 years ago
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