Under the assumption of <em>uniform</em> motion, the traveller will travel a distance of 20 feet before slowing down the vehicle to less than 40 miles per second.
<h3>How to calculate the distance taken by traveler before braking</h3>
According to this question, the vehicle travels at <em>constant</em> velocity before the traveler hit the brakes. The distance <em>traveled</em> (s), in feet, is equal to the product of velocity (v), in feet per second, and time (t), in seconds:
s = v · t (1)
If we know that v = 40 ft/s and t = 0.5 s, then the traveled distance of the vehicle is:
s = (40 ft/s) · (0.5 s)
s = 20 ft
Under the assumption of <em>uniform</em> motion, the traveller will travel a distance of 20 feet before slowing down the vehicle to less than 40 miles per second.
To learn more on uniform motion: brainly.com/question/118814
#SPJ1
10x - 8xy - 3xy
= x ( 10x - 11xy )
9514 1404 393
Answer:
17 -4i
Step-by-step explanation:
You do this the same way you would if i were a variable.
8-(-4+5i)-(-5-i) = 8 +4 -5i +5 +i = (8 +4 +5) +(-5i +i) = 17 -4i
Answer:
Step-by-step explanation:
You would write it as -4 1/2
