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4 years ago

What equation represents a parabola that opens UP with the vertex at 2,4

Mathematics

1 answer:

lubasha [3.4K]4 years ago

3 0

Answer:

y = (x -2)^2 +4

Step-by-step explanation:

The vertex form of the equation of a parabola is ...

y = a(x -h)^2 +k

for vertex (h, k) and vertical scale factor "a". When a > 0, the parabola opens upward.

One equation for your parabola could be ...

y = (x -2)^2 +4

In standard form this one is ...

y = x^2 -4x +8

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A piece of paper is in the shape of a rectangle the piece of paper is 1 5/8 inches wide and 8 3/4 inches long a student cuts of

Helga [31]

Answer : The area of the 12 equal long pieces is, $\frac{455}{6144}in^2$

Step-by-step explanation :

As we are given that:

Width of rectangle = $1\frac{5}{8}in=\frac{13}{8}in$

Length of rectangle = $8\frac{3}{4}in=\frac{35}{4}in$

When student cuts of 3/4 from width and 3/4 from height then the new width and length of rectangle will be:

New width = $\frac{13}{8}-(\frac{13}{8}\times \frac{3}{4})=\frac{13}{8}\times \frac{1}{4}=\frac{13}{32}in$

New length = $\frac{35}{4}-(\frac{35}{4}\times \frac{3}{4})=\frac{35}{4}\times \frac{1}{4}=\frac{35}{16}in$

Now student cuts in 12 equal long pieces.

New length = $\frac{\frac{35}{16}in}{12}=\frac{35}{192}in$

New width = $\frac{13}{32}in$

Now we have to calculate the area of the 12 equal long pieces.

Area of rectangle = Length × Width

Area of rectangle = $\frac{35}{192}in\times \frac{13}{32}in$

Area of rectangle = $\frac{455}{6144}in^2$

Therefore, the area of the 12 equal long pieces is, $\frac{455}{6144}in^2$

4 0

3 years ago

The answer and how you got it

mart [117]

The answer is 12
12-(5+3)=4
4+8=12

8 0

4 years ago

How to figure this problem out

Mamont248 [21]

The answer is b because the problem is starting that

5 0

3 years ago

Which lists these numbers in order from least to greatest?<br> –22.7, 126, 3.28, –3.516, 43.9

avanturin [10]

-22.7, -3.516, 3.28, 43.9, 126

4 0

3 years ago

Read 2 more answers

Charles has collected data to find that the total snowfall per year in Reamstown has a normal distribution. Using the Empirical

Mazyrski [523]

Answer:

0.8413 or 84.13%

Step-by-step explanation:

Given : The mean is 72 inches and the standard deviation is 15 inches

To Find : What is the probability that in a randomly selected year, the snowfall was less than 87 inches

Solution:

Mean = $\mu = 72$

Standard deviation = $\sigma = 15$

Formula : $z=\frac{x-\mu}{\sigma}$

We are supposed to find the probability that in a randomly selected year, the snowfall was less than 87 inches

So, x = 87

Substitute the values in the formula

$z=\frac{87-72}{15}$

$z=1$

Now to find P(z<87) refer the z table

P(Z<87)=0.8413 = 84.13%

So, the probability that in a randomly selected year, the snowfall was less than 87 inches if the mean is 72 inches and the standard deviation is 15 inches is 0.8413 or 84.13%

6 0

4 years ago