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3 years ago

Find the 92nd term of the arithmetic sequence 11, 19, 27, ...

Mathematics

1 answer:

arlik [135]3 years ago

6 0

Answer:

The 92nd term of the arithmetic sequence is 731 because the common difference between them is 8 and then I added 8 with every single number that I got and I continued adding until I get my 92nd term which is 731.

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<img src="https://tex.z-dn.net/?f=%20Simplify%3A%20%5C%3A%2018%20%5Cdiv%2016%20%2B%20%5B8%20%5C%7B16%20%5Cdiv%20%2810%20-%20%5Co

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<h3>Simplify :</h3>

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - \overline{8 - 2 } \bigg)\bigg\} \bigg]}}}}$

Simplifying vinculum bar 

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - \overline{8 - 2 } \bigg)\bigg\} \bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - 6\bigg)\bigg\} \bigg]}}}}$

Simplifying parentheses brackets

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - 6\bigg)\bigg\} \bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div 4\bigg\} \bigg]}}}}$

Simplifying curly brackets 

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div 4\bigg\} \bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{ \dfrac{16}{4} \bigg\} \bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{ \cancel{\dfrac{16}{4}} \bigg\} \bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \times 4\bigg]}}}}$

Simplifying square brackets 

${:\implies{\small{\sf{18 \div 16 + \bigg[8 \times 4\bigg]}}}}$

${:\implies{\small{\sf{18 \div 16 + 32}}}}$

According to BODMAS rule simplifying devision 

${:\implies{\small{\sf{18 \div 16 + 32}}}}$

${:\implies{\small{\sf{ \dfrac{18}{16} + 32}}}}$

${:\implies{\small{\sf{{\cancel{\dfrac{18}{16}} + 32}}}}}$

${:\implies{\small{\sf{ 1.125 + 32}}}}$

Now, according to BODMAS rule simplifying addition

${:\implies{\small{\sf{ 1.125 + 32}}}}$

${:\implies{\small{\sf{33.125}}}}$

${:\implies{\underline{\boxed{\pmb{\sf{Answer = 33.125}}}}}}$

∴ The answer is 33.125.

 $\underline{\rule{200pt}{2.5pt}}$ 

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