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Tamiku [17]
2 years ago
7

Twenty-one students took a mathematics test. The 11th highest score on the test was a 76. Which of the

Mathematics
2 answers:
qaws [65]2 years ago
5 0

give the person above me Brainliest

they deserve it                                                                :D

I think <em>that they would be greatful lol</em>

Tcecarenko [31]2 years ago
3 0

Answer:

C. The median of the test scores was 76

Step-by-step explanation:

The median is the middle value. In 21 values, the 11th value is the middle value, so it must be the median.

Answer: C. The median of the test scores was 76

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Perform the following steps to convert 8 years to days
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Find the slope of the line (7, 5) and (3, -4) on it.
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3 years ago
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Which of these could be considered a statistical question? A.How many pets does Tom have at home? B.On average, how many plants
meriva

Answer:

<h2>B. On average, how many plants do the students in your class have at home?</h2>

Step-by-step explanation:

A statistical question must have the characteristic of variability, that is, it must be a question that can be answered by a collective, where each person has a slaightly or big different answer, because all of them are different, that's the variability ingredient.

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5 0
3 years ago
Make 'h' as the subject. Remember to rationalize the denominator while solving.
Sliva [168]

Hello there BeGuiLE !

To solve your question,  we must first bring 'h' to one side of the equation.  Let's bring all the terms with the variable 'h' to the left side of the equation. So,
\large{\sf\sqrt{ 3  }  h =  1.6+h}
→ \large{\sf\sqrt{3}h-h=1.6 }

Now, let's combine the 2 terms containing the variable 'h'.
\large{\sf\sqrt{3}h-h=1.6 }
→ \large{\sf\left(\sqrt{3}-1\right)h=1.6 }

Now, we need to leave the variable 'h' alone in the left side of the equation & bring (√3 + 1) to the other side of the equation. This is done in order to make 'h' as the subject of the equation. So, we'll get it as,
\large{\sf\left(\sqrt{3}-1\right)h=1.6 }
→ \large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }

Now, let's rationalize it. Rationalizing is a process where we move the root from the denominator of a fraction to the numerator for easier calculation. So,
\large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{(\sqrt{3}-1 )(\sqrt{3}+1}) }
Now, use the algebraic identity, (a + b)(a - b) = a² - b²
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{3-1} }
→ \large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{2} }
→ \boxed{\large{\sf\:h=0.8(\sqrt{3}+1)}}

Now, we've made 'h' as the subject of the equation. If you want to solve it more, then,
\large{\sf\:h=0.8(\sqrt{3}+1)}
Take √3 as 1.73 (approx. value up to 2 decimal places)
→ \large{\sf\:h=0.8(1.73+1)}
→ \large{\sf\:h=0.8(2.73)}
→ \boxed{\boxed{\huge{\bf{\:h=2.184 \: (approx.)}}}}

I hope this will help you.

Please refer to the attached image if the explanation shows some error.

_______

Check out more links which will help you understand the topic better :

■ brainly.com/question/21406377

■ brainly.com/question/696184

_______
\mathfrak{Lucazz}


4 0
2 years ago
Read 2 more answers
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