Can someone help with this question?
1 answer:
You might be interested in
Answer:
(3,2)
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below =)
Answer:
.
Step-by-step explanation:
Let represent the mass (in pounds) of that
copper alloy required, such that the final mixture would contain
copper by mass.
Consider: if pounds of that
copper alloy is mixed with
pounds that
copper alloy, what would be the mass of copper in the mixture?
- Mass of copper in
pounds of that
copper alloy:
.
- Mass of copper in
pounds of that
copper alloy:
.
Therefore, the mixture would contain of copper.
The mass of that mixture would be . The mass fraction of copper in that mixture would be:
.
This ratio is supposed to be equal to . These two pieces of equations combine to give an equation about
:
.
.
Simplify and solve for :
.
.
.
Therefore, of that
alloy would be required.