HEY GUYS COULD YOU HELP ME WITH THESE TWO QUESTIONS!!! DON'T WORRY YOU'LL GET YOUR POINTS!!

Mathematics

2 answers:

azamat2 years ago

8 0

X+y=94 -> y=94-x
x-y=12
Substitute: x-(94-x)=12
Distribute: x-94+x=12
Simplify: 2x=106
Solve: x=53

Plug x back into equation
x-y=12
53-y=12
y=41

x= 53, y=41

Second Question:
8+x=y
x+y = 66
Substitute: x+8+x =66
Simplify: 2x+8 =66
Solve : x=29

Plug x back into equation
x+y=66
29+y=66
y = 37

x=29, y=37

LenaWriter [7]2 years ago

6 0

Answer:

i am unsure

Step-by-step explanation:

I HEART POINTS

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The maximum flow of water in a pipe is modeled by the formula Q=Av, where A is the cross-sectional area of the pipe and V is the

Ira Lisetskai [31]

For this case we have the following equation:
Q = Av
Where the area is given by:
A = pi * r ^ 2
A = pi * (d / 2) ^ 2
A = (pi / 4) * d ^ 2
Substituting we have:
Q = ((pi / 4) * d ^ 2) v
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d = root ((4 / pi) * (Q / v))
Substituting values we have:
d = root ((4 / pi) * (50/600))
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7 0

3 years ago

An airline's public relations department claims that when luggage is lost, 88% is recovered and delivered to its owner within 24

melisa1 [442]

Answer:

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

Step-by-step explanation:

Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88

At the null hypothesis, we test if the proportion is of 0.88, that is:

$H_0: p = 0.88$

At the alternate hypothesis, we test if this proportion is less than 0.88, that is:

$H_a: p < 0.88$

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.88 is tested at the null hypothesis:

This means that $\mu = 0.88, \sigma = \sqrt{0.88*0.12}$

A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.

This means that $n = 160, X = \frac{138}{160} = 0.8625$