3 years ago

Find four consecutive odd integers such that 10 more than twice the least is equal to the sum of the third and fourth.

1 answer:

6 0

Consecutive odd numbers are 2 apart

they are
x,x+2,x+4,x+6

10+2x=x+4+x+6
10+2x=2x+10
x=x
true
any consecutive odd integers will work

1,3,5,7 works
3,5,7,9 works
etc

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