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mezya [45]
3 years ago
15

Pretty please help me with this‼️

Mathematics
1 answer:
Luden [163]3 years ago
3 0

For this case we have to, the distance of both numbers will be given by the absolute value of their subtraction, that is:

d = | 4.7 - (- 11.2) | = | 4.7 + 11.2 | = | 15.9 | = 15.9

This is equivalent to:

d = | -11.2-4.7 | = | -11.2-4.7 | = | -15.9 | = 15.9

ANswer:

| 4.7 - (- 11.2) | = | -11.2-4.7 |

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I believe the answer is (-1,1) . The origin is the same as (0, 0) so I drew the line on a quick graph and if you are talking about distance, then the answer should be correct.
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6 0
3 years ago
The larger of two numbers is 15 more than 3 times the smaller number. If the sum of the two numbers is 63 find the numbers
scoray [572]

Answer:

X = 51

Y = 12

Step-by-step explanation:

2 numbers: (Larger) Number 1 is x and Number 2 is y

The equation is x + y = 63

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  • y = y

New equation is:

  • 3y + 15 + y = 63

Combine like variables:

  • 4y + 15 = 63

Solve:

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Divide 4 from each side:

  • <em><u>y = 12</u></em>

To find x fill in the variables from the 'x =' equation:

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3 0
2 years ago
Lliana rotated trapezoid WXYZ 180° about the origin.
AfilCa [17]

Answer:

The answer to the equation is W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)

Step-by-step explanation:

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6 0
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The distance d of a particle moving in a straight line is given by d(t) = 2t3 + 5t – 2, where t is given in seconds and d is mea
Sergeeva-Olga [200]

Answer:

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Step-by-step explanation:

Given the distance, d(t) of a particle moving in a straight line at any time t is:

d(t) = 2t^3 + 5t - 2, $ where t is given in seconds and d is measured in meters.

To find an expression for the instantaneous velocity v(t) of the particle at any given point in time, we take the derivative of d(t).

v(t)=\dfrac{d}{dt}\\\\v(t) =\dfrac{d}{dt}(2t^3 + 5t - 2) =3(2)t^{3-1}+5t^{1-1}\\\\v(t)=6t^2+5

The correct option is C.

6 0
2 years ago
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