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3 years ago

WRITING ASSIGNMENT for math pls help me

Mathematics

1 answer:

Mashcka [7]3 years ago

8 0

We can’t do writing assignments go to the writing section.

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- 3x + 4 and passes through the point (2,5)

Anuta_ua [19.1K]

Answer:

y=(x+13)/3

Step-by-step explanation:

the question is not quite clear, i think u mean y= -3x + 4

then, the slope of the line perpendicular to the given line is m1.m2= -1, hence, -3.m2= -1 m2 = 1/3

y-5=1/3(x-2) y=x/3+13/3 or y=(x+13)/3

6 0

3 years ago

B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =

jolli1 [7]

I suppose you mean

$g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)$

Differentiate one term at a time.

Rewrite the first term as

$\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}$

Then the product rule says

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'$

Then with the power and chain rules,

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}$

Simplify this a bit by factoring out $\frac12 (36-x^2)^{-3/2}$ :

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}$

For the second term, recall that

$\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}$

Then by the chain rule,

$\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}$

So we have

$g'(x) = 18 (36-x^2)^{-3/2} + 18 (36-x^2)^{-1/2}$

and we can simplify this by factoring out $18(36-x^2)^{-3/2}$ to end up with

$g'(x) = 18(36-x^2)^{-3/2} \left(1 + (36-x^2)\right) = \boxed{18 (36 - x^2)^{-3/2} (37-x^2)}$

5 0

2 years ago

What is the equation of the line parallel to the line with the equation −x+3y=−3

mezya [45]

Answer:

y = 1/3x - 19/3

Step-by-step explanation:

3y = x -3

y = 1/3x -3

Slope = 1/3

Point= (1,-6)

y-intercept = -6 - (1/3)(1) = -6 - 1/3 = -19/3

5 0

2 years ago

Bill works for the Stuff It Mailing Service. He receives 25 cents for each document he puts together and prepares for

KATRIN_1 [288]

Answer:

(a)Bill's Total piecework pay =$500

(b)Amount owed by his boss=$26

Step-by-step explanation:

Let the number of documents put together and prepared for mailing by Bill =x

Bill receives 25 Cents=$0.25 for every document

Therefore for x documents, Bill should receive: $0.25x

If Bill prepared 2000 documents for mailing

x=2000

The amount he should receive = $0.25 X 2000 =$500

(a)Bill's Total piecework pay =$500

(b)Amount owed by his boss

=500-474

=$26

3 0

3 years ago

Robyn uses cup of blueberries to make each loaf of blueberry bread. Explain how many loaves of blueberry bread she can make with

tekilochka [14]

Answer:

2 loaves of blueberry bread

Step-by-step explanation:

for 1 loaf of bread she uses 1 cup

for 2 loaves she will use 2 cupa

7 0

3 years ago