Answer:
triangle A andC are the same
Answer:
I think its 229
if you take how many yellow marbles he got out of 7 it would be 3/7 and then I divided 400 by 7 and got 57. something so I multiplied 3 times 57 and got 171. So if you take 400-171 you get 229
<h2>
Hello!</h2>
The answer is: D) 6.2 seconds
<h2>
Why?</h2>
When the egg hit the ground, the height will be equal to 0, so, from the given equation we need to find the roots or zeroes.
It's a quadratic function, we can find the roots using the quadratic equation:
So, from the given function we know that:
So, substituting we have:
So, since the time can not be a negative value, the correct option is:
6.18≈6.2 seconds
Hence, it takes 6.2 seconds to the egg to hit the ground.
Have a nice day!
Answer:
see explanation
Step-by-step explanation:
Using Pythagoras' theorem, that is
The square on the hypotenuse of a right triangle is equal to the sum of the squares on the other two sides.
Using x instead of ?
(a)
The hypotenuse is the side opposite the right angle, that is 74, thus
24² + x² = 74²
576 + x² = 5476 ( subtract 576 from both sides )
x² = 4900 ( take the square root of both sides )
=
x = 70
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(b)
The hypotenuse x is the unknown side here
x² = 40² + 40² = 1600 + 1600 = 3200
Take the square root of both sides
= ≈ 56.6 ( nearest tenth )
Step-by-step explanation:
In order to graph this system of equations, you have to put the equations in terms of y so that you can graph it by hand.
For the first equation:
Subtract x on both sides so that it reads to be
For the second equation:
Subtract 3x on both sides and divide by -1 to make the y positive. Remember that when you divide, the sign always flips:
So the two equations you have to graph now are and .
In order to graph, start from your y-intercept for each of the equations and go vertical/horizontal based on the coefficient of your equation. For instance, for your first equation, you would go down -1 and to the right 1. Repeat until your whole equation is graphed. For the second equation your coefficient is 3, so you would go up 3 from -4 and to the right 1. Repeat.
Once you have your equations graphed, you need to find where the two graphs both have solutions. To do this, pick any point from the graph and plug it into the x and y of one equation. If the equation equals itself, then that area is the solution of the graph for that equation. Make sure to do this for both equations. Once you find the area in which both equations have solutions for each other, that is the area that needs to be shaded.
Here is what your graph should look like: