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3 years ago

Please refer to the attachment for clear.. Need help please.

Mathematics

1 answer:

umka21 [38]3 years ago

5 0

Hello There!

The answer you have selected, (D) is correct!

To get the answer you simply add the two fractions together. and 9 + 4 = 13.

13/10 is also called an irrational fraction, the more you know~

Have a great day, and maybe brainliest?

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Black_prince [1.1K]

-4x+9x=5x

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answer is 5x+3

I hope I am right

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Right triangle XYZ has right angle Z. If the sin(X)=1213<br> , what is the cos(X)

AlekseyPX

Given:

Right triangle XYZ has right angle Z.

$\sin(x)=\dfrac{12}{13}$

To find:

The value of $\cos x$ .

Solution:

We know that,

$\sin^2(x)+\cos^2(x)=1$

$\cos^2(x)=1-\sin^2(x)$

$\cos(x)=\pm\sqrt{1-\sin^2x}$

For a triangle, all trigonometric ratios are positive. So,

$\cos(x)=\sqrt{1-\sin^2x}$

It is given that $\sin(x)=\dfrac{12}{13}$ . After substituting this value in the above equation, we get

$\cos(x)=\sqrt{1-(\dfrac{12}{13})^2}$

$\cos(x)=\sqrt{1-\dfrac{144}{169}}$

$\cos(x)=\sqrt{\dfrac{169-144}{169}}$

$\cos(x)=\sqrt{\dfrac{25}{169}}$

On further simplification, we get

$\cos(x)=\dfrac{\sqrt{25}}{\sqrt{169}}$

$\cos(x)=\dfrac{5}{13}$

Therefore, the required value is $\cos(x)=\dfrac{5}{13}$ .

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3 years ago

What is the solution of 2x/5−x/2=40 ?

mrs_skeptik [129]

2x/5 - X/2 = 40
LCD = 10

2•(2x/5) - 5•(X/2) = 40
4x/10 - 5x/10 = 40
4x-5x/10 = 40
-X/10 = 40
10•(-X/10) = 40 • 10
-X = 400
-X/-1 = 400/-1
X = -400.

I believe the solution is that X = -400.

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4 years ago