Sixty people are invited to a party. There are 24 cup in a package and 18 napkins in a package. What is the least number of pack ages of cups and napkins that can be bought if each party guest get one cup and one napkin?
1 answer:
Answer:
3 packages of cups 4 packages of napkins Step-by-step explanation:
You need at least enough for 60, so any requirement for a partial package means you need to buy another whole package. The "ceiling" function gives the next higher integer for a non-integer value.
cups = ceiling((60 cups)/(24 cups/package)) = ceiling(2.5) packages
= 3 packages
__
napkins = ceiling((60 napkins)/(18 napkins/package))
= ceiling(3 1/3) packages = 4 packages
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Does this help? If it doesn't i can try to explain more if you want.
We know, Volume of a Cylinder = πr² h/3 v = 3.14 * 4² * 6/3 v = 3.14 * 16 * 2 v = 100.48 In short, Your Answer would be Option B Hope this helps!
It looks as though you missed a number, but you would factor out an x or a y to get your answer and subtract the whole thing
Answer:
AC, CE, AB, and AS
I belive those are your answers
D) Reflective Property: Given UVW=WXU is given and the UW=UW is proven by reflexive property because share the same side