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nataly862011 [7]
3 years ago
12

Sixty people are invited to a party. There are 24 cup in a package and 18 napkins in a package. What is the least number of pack

ages of cups and napkins that can be bought if each party guest get one cup and one napkin?
Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

  • 3 packages of cups
  • 4 packages of napkins

Step-by-step explanation:

You need at least enough for 60, so any requirement for a partial package means you need to buy another whole package. The "ceiling" function gives the next higher integer for a non-integer value.

  cups = ceiling((60 cups)/(24 cups/package)) = ceiling(2.5) packages

  = 3 packages

__

  napkins = ceiling((60 napkins)/(18 napkins/package))

  = ceiling(3 1/3) packages = 4 packages

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I need the answer to this question please help me
pogonyaev

Answer:

38

Step-by-step explanation:

<u>Step 1:  Since RYH and BYH are complimentary, they add up to 90</u>

<em>2f + 58 + 8f + 62 = 90</em>

<em />

<u>Step 2:  Combine like terms</u>

2f + 58 + 8f + 62 = 90

<em>10f + 120 = 90</em>

<em />

<u>Step 3:  Subtract 120 from both sides</u>

10f + 120 - 120 = 90 - 120

10f / 10 = -30 / 10

<em>f = -3</em>

<em />

<u>Step 4:  Find RYH</u>

RYH = 8f + 62

8(-3) + 62

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<em>38</em>

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Answer:  38

4 0
3 years ago
The initial freshman class at a college is 10% smaller 1
Harman [31]

Answer:

875 students are enrolled in this year's freshman class after the first week of classes.

Step-by-step explanation:

Last year, there were 950 students.

This year, the class is 10% smaller. So it's number of students is 100 - 10 = 90% of last year.

0.9*950 = 855

Initially, this year class had 855 students.

During the first week, 20 enrolled.

855 + 20 = 875.

So

875 students are enrolled in this year's freshman class after the first week of classes.

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Step-by-step explanation:

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In circle J with \text{m} \angle HLK= 30^{\circ}m∠HLK=30
olga2289 [7]

Answer:

The minor arc HK is 60 degrees

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The inscribed angle is half that of the arc it comprises.

so

m\angle HLK=\frac{1}{2}(arc\ HK)

we have

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therefore

The minor arc HK is 60 degrees

8 0
3 years ago
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