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alisha [4.7K]
3 years ago
8

. Two friends pooled the tickets they won from playing video games to get a prize that requires 500 tickets. If one friend won 8

0 more tickets than the other friend, how many tickets did each friend win
Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:

Friend 1 (with 80 more tickets) gets 290

Friend 2 gets 210

Step-by-step explanation:

500-80 = 420 tickets |

^in order to figure out how many total tickets they got without the 80 extra

420/2 = 210 |

^divide by 2 to figure out how many tickets each friend had

210+80 |

^add 80 to figure out how many tickets friend one gets

<u>210</u><u> </u><u>+</u><u> </u><u>290</u><u> </u><u>=</u><u> </u><u>500</u>

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DENIUS [597]
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a = 7 , b = -1 , c = -9

x = \frac{-b \pm  \sqrt{b^2 - 4ac} }{2a}   Plug in the a, b, and c values
x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
x = \frac{1 \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Square -1
x = \frac{1 \pm  \sqrt{1 - 4(7)(-9)} }{2(7)}   Multiply 7 and -9
x = \frac{1 \pm  \sqrt{1 - 4(-63} }{2(7)}   Multiply -4 and -63
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x = \left \{ {{ \frac{1 +  \sqrt{253} }{14} } \atop { \frac{1 -  \sqrt{253} }{14} }} \right.
The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
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x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
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Step-by-step explanation:

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3 years ago
Eighth grade
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Answer:

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Step-by-step explanation:

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