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3 years ago

If I have 3 shoes, 9 Blouses, 8 pants, 11 belts. How many different kind of outfits can I make

Mathematics

1 answer:

Oduvanchick [21]3 years ago

6 0

Well you can make more than 8

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What is the difference between −5x+7 and 3x−2?

julia-pushkina [17]

Answer:

-5x+7-(3x-2)

=-5x+7-3x+2

=-8x+9

Step-by-step explanation:

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3 years ago

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Artemon [7]

Answer:

the answer is 1,2 and 4 hope it helps

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3 years ago

marvin the math magician has a problem for you. he wants to buy some magic wands and some magic hats. the wands cost $8 each and

tensa zangetsu [6.8K]

He will pay $131 for all that stuff

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3 years ago

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6.<br> Domain:<br> Range:<br> can someone please help me

ra1l [238]

Answer:

Domain: the set of possible values of the independent variable or variables of a function.

Range: the set of values that a given function can take as its argument varies.

Step-by-step explanation:

Hopefully this helps ik it was confusing to me too in pre-algebra when i was in 8th grade

have a great day

4 0

3 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

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3 years ago