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natima [27]
3 years ago
5

Please answer correctly !!!!!!! Will mark Brianliest !!!!!!!!!!!

Mathematics
1 answer:
Westkost [7]3 years ago
3 0

Answer: if simpliflying the answer is -4+3y

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For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
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Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

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To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

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It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

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230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

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Substituting y in (1)

x = 20 +15

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