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natima [27]
3 years ago
5

Please answer correctly !!!!!!! Will mark Brianliest !!!!!!!!!!!

Mathematics
1 answer:
Westkost [7]3 years ago
3 0

Answer: if simpliflying the answer is -4+3y

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Please please help meeee
Daniel [21]

Answer:

1.5 km

Step-by-step explanation:

Length of pool = 25m

no.of lengths. = 60

Total length of he swim s = 25m* 60

= 1500m

You know , 1000m = 1km ,

so,

He swims 1500m/1000m

= 1.5 km

4 0
3 years ago
What is the solution set of this inequality? 3|p + 4| + 5 < 8 (–5, –3) (–3, 0) (0, –5) (3, 5)
Viefleur [7K]

Given:

The inequality is

3|p+4|+5

To find:

The solution set for the given inequality.

Solution:

We have,

3|p+4|+5

3|p+4|

3|p+4|

Divide both sides by 3.

|p+4|

It can be written as

-1

Subtracting 4 from each side, we get

-1-4

-5

The solution set of the given inequality is (-5,-3).

Therefore, the correct option is A.

7 0
2 years ago
A large diamond with a mass of 481.3 grams was recently discovered in a mine. If the density of the diamond is 3.51 , what is th
sineoko [7]

Answer:

137.12

Step-by-step explanation:

Density = mass/volume

Density = 3.51

Mass = 481.3

Thus: 481.3/3.51 = 137.122507123

6 0
3 years ago
Read 2 more answers
Use the ratio go solve the percent problem
Drupady [299]
Answer
40%
32 is what percent of 80? =40.
5 0
3 years ago
In 2012, about 24% of high-school seniors reported binge drinking (defined as five or more drinks in a row in the past two weeks
Artist 52 [7]

Answer: (0.24 - 1.96*0.019, 0.24 + 1.96*0.019)

Step-by-step explanation:

We know that the confidence interval population proportion (p) is given by :-

\hat{p}\pm z*\cdot SE

, where \hat{p} = sample proportion.

z* = Critical value (Two -tailed)

SE = standard error

Given : In 2012, about 24% of high-school seniors reported binge drinking (defined as five or more drinks in a row in the past two weeks), a substantial drop since the late 1990s.

\hat{p}=0.24

SE = 0.019

Significance level =\alpha=1-0.95=0.05

Two-tailed value corresponds for \alpha=0.05 :

z*=1.96   [Using z-table]

Now, the 95% confidence interval for the proportion of high-school seniors in the sample who would report binge drinking will be :-

0.24\pm (1.96)\cdot (0.019)=(0.24-1.96\times 0.019,\ 0.24+1.96\times 0.019)

Hence, the correct answer = (0.24 - 1.96*0.019, 0.24 + 1.96*0.019)

8 0
3 years ago
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