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3 years ago

0.30 meters to customary units of length

Mathematics

1 answer:

Vlada [557]3 years ago

8 0

It would be .98 feet or 11.81 inches

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ArbitrLikvidat [17]

Answer: Angles 4 and 5

Step-by-step explanation:

Supplementary angles are angles that add up to 180. The only angle pairs the add up to 180 (you can tell by seeing if two angles are the only two on a straight line) are angles 4 and 5, and angles 3 and 4. Angles 3 and 4 isn’t an option, so it’s 4 and 5.

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2 years ago

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Help please! I'm stuck with all these numbers :(

yuradex [85]

Answer:

Step-by-step explanation:

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3 years ago

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I have 2 congruent, parallel, rectangular bases.

Anit [1.1K]

Answer:

The 3D figure formed is a <u>Cuboid</u><u>.</u>

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3 years ago

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Fill in the missing work and justification for step 2 when solving 3(x + 2) = 12.

liq [111]

Answer:

Step-by-step explanation:

3(x+2)=12

Distribute:

3x+6=12

Subtract:

3x+6-6=12-6

3x=6

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x=2

4 0

3 years ago

Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).

lions [1.4K]

Check the picture below. so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}$

$(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill$

$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}$

6 0

2 years ago