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6 months ago

If s(x) = 2 - x and t(x) = 3x, which value is equivalent to (s•f)(-7)?

Mathematics

1 answer:

erica [24]6 months ago

4 0

Answer:

Step-by-step explanation:

t(-7)= 3(-7)= -21

s(-21)= 2-(-21)= 2 + 21= 23

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Explain how you would order from the least to the greatest three numbers that include a positive number, a negative number, and

jeyben [28]

Well, zero is between negative and positive numbers. Negative number are less than zero and positive numbers. Positive number are greater than negative number and zero. And, zero is greater than negative number but smaller than positive number.

Negative number < Zero < Positive number

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2 years ago

SR = 3, RT = 1, ST =

White raven [17]

Answer:

since R seems to be in middle between ST

ST=3+1=4

Step-by-step explanation:

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2 years ago

Tatum wants to use partial products to find 15x32

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3 years ago

11. El 9 de enero venden a crédito a Stan Lee Co las siguientes mercancías: 4

Allushta [10]

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2 years ago

The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among

jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(d) The event is not unusual.

Step-by-step explanation:

Let X = number of households watching the show.

The probability of the random variable x is, P (X) = p = 0.18.

The sample selected for the survey is of size, n = 14

The random variable X follows a Binomial distribution with parameter n = 14 and p = 0.18.

The probability of a Binomial distribution is computed using the formula:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...$

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

$P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062$

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-0.062\\=0.938$

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

$={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253$

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0

3 years ago