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Flura [38]
3 years ago
13

Can someone help me with N please

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
7 0
Let's assume x Mo's number.

11+x/3=-1
==>x/3=-1-11
==>x/3=-12
==>x=-12*3
==>x=-36

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I’ll give brainliest please help
sammy [17]

Answer:

m=4

Step-by-step explanation:

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3 years ago
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The measure of XYZ is 45. The length of radius YZ is 6 inches. What is the area of sector XYZ?
balandron [24]

Answer:

area of a sector = 14.13 yards²

Step-by-step explanation:

XYZ is a sector of a circle. The radius YZ is 6 inches .The angle of the sector is given as 45°. The area of the sector can be solved as follows.

area of a sector = ∅/360 × πr²

where

r = radius

∅ = center angle

r = 6 inches

∅ = 45°

area of a sector = 45/360 × 3.14 × 6²

area of a sector = 45/360 × 3.14 × 36

area of a sector = 45/360 × 113.04

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3 years ago
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4. Which ordered pair is a solution of 3y + 2 = 2x - 5?
Lyrx [107]

Answer:

we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

Step-by-step explanation:

Considering the equation

3y\:+\:2\:=\:2x\:-\:5

  • Putting (-5,2) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(2\right)\:+\:2\:=\:2\left(-5\right)\:-\:5

8=-15         ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (0,-5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(-5\right)\:+\:2\:=\:2\left(0\right)\:-\:5

-13=-5       ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (5,1) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(1\right)+\:2\:=\:2\left(5\right)-\:5

5\:=-5          ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (7,5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(5\right)+\:2\:=\:2\left(7\right)-\:5\:\:

17=9          ∵ L.H.S ≠ R.H.S

FALSE

From the above calculations, we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

4 0
3 years ago
PLEASE HELP. ITS A MINI-QUIZ / HOMEWORK AND ITS TRIANGLES.
polet [3.4K]

Answer:

76 degrees

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180-104 is 76 since it's a straight line which equals to 180 degrees

3 0
3 years ago
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You toss a pair of dice. (a determine the number of possible pairs of outcomes. you toss a pair of dice. (a determine the number
Eduardwww [97]
(a) ^{6}C_1 * ^{6}C_1 = 36 different possibilities
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P(even die 2): \frac{1}{2}

So, there is a 1 in 4 chance that both dice will show an even.
3 0
3 years ago
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