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Mademuasel [1]
3 years ago
15

Divide. 8.844 ÷ 0.04 = and Divide. 0.48 ÷ 120 =

Mathematics
1 answer:
miskamm [114]3 years ago
6 0
221.1 and .0004 are the answers.
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What is the slope of the line? Anwer
amm1812
The slope of the line is 1/3
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3 years ago
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Maria stated that 5/6 is between 4/5 and 6/7
Vlada [557]

Answer:

It's true, if that's what your asking.

Step-by-step explanation:

5/6 = 0.833 to 3 sig.fig.

4/5 = 0.800 to 3 sig.fig.

6/7 = 0.857 to 3 sig.fig.

0.833 is more than 0.800 and less than 0.857.

3 0
3 years ago
Tyson bought four roses for $8.88. If the cost per rose is constant, how much would 6 roses cost?
jeka94

Answer:

6 roses = $13.32

Step-by-step explanation:

4 roses = $8.88

(divide by 4)

1 rose = $2.22

(multiply by 6)

6 roses = $13.32

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3 years ago
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Kiran scored 36 baskets in 1 week. She scored 1/2 of the baskets on the weekend. She scored 1/4 of them on Tuesday, she scored 1
notka56 [123]

Answer:

6 baskets did Kiran score on Thursday

Step-by-step explanation:

As per the statement:

Kiran scored 36 baskets in 1 week.

On weekend she scored = \frac{1}{2} \cdot 36 = 18 baskets.

She scored 1/4 of them on Tuesday

⇒On Tuesday she scored = \frac{1}{4} \cdot 36 = 9 baskets

She scored 1/12 of them on Wednesday

⇒On Wednesday she scored = \frac{1}{12} \cdot 36 = 3 baskets.

Then;

She scored = On Weekend + On Tuesday + On Wednesday = 18+9+3 = 30 baskets.

Rest on Thursday she scored = 36 - 30 = 6 baskets.

Therefore, 6 baskets did Kiran score on Thursday

8 0
3 years ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0
1 year ago
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