Let's put this in terms of a system of equations. Let's call the numbers x and y, with x being the larger integer and y the smaller one. Since they are consecutive odd integers, we know that:
x = y + 2
The constraint is:
xy= 3(x+y) + 71 Simplify
xy = 3x + 3y + 71 Plug in (y+2) for x:
(y + 2) y = 3(y + 2) + 3y + 71 Simplify
y² + 2y = 3y + 6 + 3y + 71 Subtract 6y from both sides, add 71+6
y² -4y = 77
y² - 4y - 77 = 0
Factor:
(y - 11) (y+7) = 0
y = 11 or y=-7
When y = 11, x = 13, since x = y+2
Plug in to make sure:
xy = 3(x+y) + 71
11*13 = 3 (11 + 13) + 71
143 = 3 (24) + 71
143 = 72 + 71
143 = 143
Our values work!
Answer: 11, 13
Answer:18
Step-by-step explanation:4(-3) = -12, and 40-12=18
<u><em>Answer:</em></u>
Nelson burned the most calories per hour
<u><em>Explanation:</em></u>
To solve this question, we will get the amount calories burned by each in one hour and then compare the two values
To do this, we will divide the total amount of calories burned by the total time
<u>1- For Sabra:</u>
We are given that she burnt 845 calories in
(which is equivalent to 3.25) hours
<u>Therefore:</u>
Calories burnt in an hour =
calories/hour
<u>2- For Nelson:</u>
We are given that he burnt 1435 calories in
(which is equivalent to 4.875) hours
<u>Therefore:</u>
Calories burnt in an hour =
calories/hour
<u>3- Comparing the two values:</u>
From the above calculations, <u>we can deduce that</u> Nelson burned the most calories per hour
Hope this helps :)
Answer:
1,000,000
Step-by-step explanation: