Triangle ABD is i<span>nscribed in circle and </span>has hypotenuse as circle's diameter so angle ABD must be 90°
Since it is parallelogram, ∠ABD = ∠BDC = 90° and it is given that ∠ADB = 30°
So we have ∠CDO = ∠CDB + ∠ADB = 30° + 90° = 120°
Final answers: ∠CDO = 120° and ∠ABD = 90°
Uv al dt or trace mcsorely
Write the conjugates of them then FOIL both the top and bottom, then factor
Step-by-step explanation:
Here
5x+16+7x-3+6x+5 = 180(being sum of triangle)
or, 18x=180-18
or, x= 162/18
so, x = 9
now,
here,
<ACD = <ACB(diagonals of parallelogram bisect eachother)
or, <ACD = 7x-3
or, <ACD = 7×9-3
or, <ACD = 63-3
So, <ACD = 60°
<span>step 1 :</span> 3 • (x - 9) - 30 = 0
<span>Step 2 :</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
3x - 57 = 3 • (x - 19)
<span>Equation at the end of step 3 :</span> 3 • (x - 19) = 0
<span>Step 4 :</span>Equations which are never true :
<span> 4.1 </span> Solve : 3 = 0
<span>This equation has no solution.
</span>A a non-zero constant never equals zero.
Solving a Single Variable Equation :
<span> 4.2 </span> Solve : x-19 = 0<span>
</span>Add 19 to both sides of the equation :<span>
</span> x = 19
One solution was found : <span> x = 19</span>
