What is 14 × 25 × 4 in friendly numbers?

There are two different loci that cause white coat color in horses. One locus is the albino locus found in all mammals. Albinism

julsineya [31]

Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.

Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w. Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:

1/16 CCWW (lethal)

2/16 CCWw (white)

2/16 CcWW (lethal)

4/16 CcWw (white)

1/16 CCww (normal)

2/16 Ccww (normal)

2/16 ccWw (albino)

1/16 ccWW (lethal)

1/16 ccww (albino)

Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.

8 0

3 years ago

Simplifying rational expressions

Sonbull [250]

1. $\frac{(c + 8)(c - 8)}{(c - 8)(c + 3)}_,_$
   $\frac{c + 8}{c + 3}_,_$

2. $\frac{n^{2} + 4n - 12}{n^{2} + 2n - 8}_,_$
   $\frac{n^{2} + 6n - 2n - 12}{n^{2} + 4n - 2n - 8}_,_$
   $\frac{n(n) + n(6) - 2(n) - 2(6)}{n(n) + n(4) - 2(n) - 2(4)}_,_$
   $\frac{n(n + 6) - 2(n + 6)}{n(n + 4) - 2(n + 4)}_,_$
   $\frac{(n - 2)(n + 6)}{(n - 2)(n + 4)}_,_$
   $\frac{n + 6}{n + 4}_,_$

3. $\frac{42x^{2}y^{3}}{28x^{3}y}_,_$
   $\frac{3y^{2}}{2x}_,_$

4. $\frac{m^{2} - 3m - 10}{m - 5}_,_$
   $\frac{m^{2} - 5m + 2m - 10}{m - 5}_,_$
   $\frac{m(m) - m(5) + 2(m) - 2(5)}{m - 5}_,_$
   $\frac{m(m - 5) + 2(m - 5)}{m - 5}_,_$
   $\frac{(m + 2)(m - 5)}{m - 5}_,_$
   $m + 2_,_$

3 0

3 years ago

Please helo with thos question pleas

natta225 [31]

The sum of the opposite interior angles is equal to the exterior angle.

So,

∠CAB + ∠ACB = ∠CBD

x + 40 + 3x + 10 = 6x

4x + 50 = 6x

2x = 50

x = 25°

∠CAB = x + 40 = 25 + 40 = 65°

Hence, the answer is D.

4 0

3 years ago

A Family purchased tickets to the movies in spent a total of $40.75. The family purchase five tickets there was a $.90 processi

muminat

Answer:

$7.25

Step-by-step explanation:

Total amount spent on the ticket = $40.75

Number of ticket purchased = 5

Processing fee per ticket = $0.90

Unknown:

Cost of each ticket = ?

Solution:

To solve this problem, we need to find the processing fee for the 5 tickets purchase;

Processing fee = number ticket x processing fee per ticket

Processing fee = 5 x 0.9 = $4.5

Now, the real cost a ticket = $40.75 - $4.5 = $36.25

So, cost per ticket is;

Cost = $\frac{36.25}{5}$ = $7.25

7 0

3 years ago

Clare went to a concession stand that sells pretzels for $3.25, drinks for $1.85, and bags of popcorn for $0.99 each. She bought

djyliett [7]

Answer:

No.

Step-by-step explanation:

Price of each pretzel = $3.25

Price of each drink = $1.85

Price of each bag of popcorn = $0.99

Maximum money to be spent = $10

Price of two pretzels = $3.25 $\times$ 2 = $6.5

Price of two drink = $1.85 $\times$ 2 = $3.70

Price of two bags of popcorn = $0.99 $\times$ 2 = $1.98

Total money spent for buying two items of each type = $6.5 + $3.70 + $1.98 = $12.18

The money spent when 2 pretzels, 2 drinks and 2 bags of popcorn are bought is $12.18.

But maximum money available is $10.

Therefore, Clare would not be able to buy 2 pretzels, 2 drinks and 2 bags of popcorn with the amount of money available.

7 0

3 years ago