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dolphi86 [110]
4 years ago
5

Solve 2x2 + 12x - 14 = 0 by completing the square

Mathematics
1 answer:
vovangra [49]4 years ago
5 0

Answer:

<h2>x = -7 or x = 1</h2>

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\\\2x^2+12x-14=0\qquad\text{divide both sides by 2}\\\\x^2+6x-7=0\qquad\text{add 7 to both sides}\\\\x^2+2(x)(3)=7\qquad\text{add}\ 3^2=9\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=7+9\\\\(x+3)^2=16\Rightarrow x+3=\pm\sqrt{16}\\\\x+3=-4\ or\ x+3=4\qquad\text{subtract 3 from both sides}\\\\x=-7\ or\ x=1

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The correct question is
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Orlov [11]
Below is the solution: 

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<span>A=(s)^2 A=16cm^2 , s=sqrt(A) , s=sqrt(16) , s=4cm </span>

<span>da/dT=2(s)(6cm/sec) , da/dT=12cm/sec(s) , da/dT=12cm/sec (4cm) 
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<span>Answer should be da/dT=48cm^2/sec
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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

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