There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
11
Step-by-step explanation:
11*2=22, 22+14=36, quick maths
Answer:
Seven numbers.
Step-by-step explanation:
Finding the numbers, which are equal to the sum of two odd number and it has to be single digit number.
Lets look into numbers which are odd and single digit.
1 = 
∴ Sum of the number is 
3 = 
∴ Sum of above number is 
5 = 
∴ Sum of above number is 
7= 
∴ Sum of above number is 
Now, accumlating numbers which are fullfiling the criteria, however, making sure no number should get repeated.
∴ Numbers are: 
Hence, there are total 7 numbers, which are equal to the sum of two odd, one-digit numbers.
Answer:
Angle PTR and angle PTS are supplementary angles. Lines PQ and RS intersect at an angle less than a right angle. Angle PTR and angle PTS are complementary angles.
Step-by-step explanation:
The last one is that correct answer.
2x^2 +7x -4
